HW8 Solution - Chapter 4, Problem 40. Find the Thevenin...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 4, Problem 40. Find the Thevenin equivalent at terminals a-b of the circuit in Fig. 4.107. + _ 70 V + V o 4 V o + 10 k Ω 20 k Ω c c b a I Figure 4.107 For Prob. 4.40. Solution. To obtain V Th , we apply KVL to the loop. 70 (10 20) 4 0 o kI V −+ + + = But 10 o Vk = I 70 70 1 kI I mA =⎯ →= 70 10 0 60 V Th Th kI V V + = To find R Th , one approach is to remove the 70-V source and apply a 1-V source at terminals a-b, as shown in the circuit below. V th =60.0V 1 V We notice that V o = -1 V. 11 12 0 4 0 0 . 2 5 m A o kI V I + = ⎯⎯ 21 1 0.35 mA 10 V II k =+ = 2 2.857 k 0.35 Th V Rk I == Ω = Ω b 20k Ω o 10 k Ω + _ + V o I 2 a I 1 f c + 4 V R th = 2.86k Ω 1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Chapter 4, Problem 43. Find the Thevenin equivalent looking into terminals a - b of the circuit in Fig. 4.110 and solve for i x . The 6 ohm resistor is a load resistance. Figure 4.110 Solution. To find R Th , consider the circuit in Fig. (a). Remove the 6 ohm load resistor. (a) 10 Ω R Th a b 10 Ω 5 Ω (b) 10 Ω 20V + 2 A 10 Ω V Th + + v a + v b 5 Ω b a R Th = 10||10 + 5 = 10.0 ohms To find V Th , consider the circuit in Fig. (b).
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 8

HW8 Solution - Chapter 4, Problem 40. Find the Thevenin...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online