Math_137_Winter_2010_Solution_9

# Math_137_Winter_2010_Solution_9 - Math 137 Winter 2010...

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Math 137 Winter 2010 Assignment 9 Due Wednesday, March 31 All solutions must be clearly stated and fully justified. Use the format given on UW-Ace under Content, in the folder Assignments; it is the file Math 137 Assignment Templates . Text problems: Section 4.9: 14, 28, 30, 44, 72 Section 5.2: 6, 18, 52 Section 7.7: 8, 20, 28, 32 Section 5.3: 8, 18, 30, 40 Section 5.4: 12, 18, 44, 52 Section 5.5: 8, 16, 20, 26, 30, 36, 46, 58, 66, 78 Section 4.9: 14. Find the general antiderivative of f(x) = 3e x + 7 sec 2 x 28. Find f if f ″′ (t) = t – t 30. Find f if f (x) = 8x 3 + 12x + 3, f(1) = 6 44. Find f if f (t) = 2e t + 3 sin t, f(0) = 0, f( π ) = 0 72. A car is traveling at 50 mi/hr when the brakes are fully applied, producing a constant deceleration of 22 ft/sec 2 . What is the distance traveled before the car comes to a stop? We need one system of measurements, say feet and seconds. So 50 mi/hi = 50 [5280 ft/mi ] / [3600 seconds/hr] mi/hr = 220/3 = 73.333 ft/sec. Say that t=0 when the driver hits the brakes. Acceleration is a(t) = – 22 v(t) = – 22t + 220/3 s(t) = – 22t 2 /2 + 220t/3 + s(0) = – 11t 2 + 220t/3 + s(0). The car comes to a stop when v(t) = 0 t = 220/(22*3) = 10/3 sec, and the

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distance traveled is s(10/3) – s(0) = – 11(10/3) 2 + 220(10/3)/3 = – 1100/9 + 2200/9 = 1100/9 122.22 ft. Section 5.2:
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Math_137_Winter_2010_Solution_9 - Math 137 Winter 2010...

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