HW2Solutions

HW2Solutions - = HYPGEOMDIST(0,5,4,52) = .6588 d. 1 - f (0)...

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5E Fall 2010 Homework 2 Solutions Chapter 4: 45. a. Let S = person is age 65 or older P (S) = 34,991,753 .12 281,421,906 b. Let D 5 = takes 5 or more prescriptions P ( S | D 5 ) = 5 5 5 ( ) ( ) ( ) ( ) ( ) ( ) c c P S P D S P S P D S P S P D S = .12(.40) .12(40) .88(.28) = .048 .048 .2464 = .16 Chapter 5: 12. a. Yes; f ( x ) 0. f ( x ) = 1 b. f (500,000) + f (600,000) = .10 + .05 = .15 c. f (100,000) = .10 22. a. E ( x ) = x f ( x ) = 300 (.20) + 400 (.30) + 500 (.35) + 600 (.15) = 445 The monthly order quantity should be 445 units. b. Cost: 445 @ $50 = $22,250 Revenue: 300 @ $70 = 21,000 $ 1,250 Loss 32. a. .90 c. P (at least 1) = 1 - f (0) 0 3 3! (0) (.9) (.1) .001 0! 3! f Therefore, P (at least 1) = 1 - .001 = .999 d. Yes; P (at least 1) becomes very close to 1 with multiple systems and the inability to detect an attack would be catastrophic.
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5E Fall 2010 65. Hypergeometric N = 52, n = 5 and r = 4. c. 4 48 0 5 1,712,304 52 2,598,960 5  
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Unformatted text preview: = HYPGEOMDIST(0,5,4,52) = .6588 d. 1 - f (0) = 1 - .6588 = .3412 Chapter 6: 18. = 30 and = 8.2 a. At x = 40, 40 30 1.22 8.2 z P ( z 1.22) = .8888 P ( x 40) = 1 - .8888 = .1112 Using Excel: =1-NORMDIST(40,30,8.2,TRUE) = .1113 (you wont have Excel during test, learn to use tables) b. At x = 20, 20 30 1.22 8.2 z P ( z -1.22) = .1112 So, P ( x 20) = .1112 Using Excel: =NORMDIST(20,30,8.2,TRUE) = .1113 (you wont have Excel during test, learn to use tables) c. A z-value of 1.28 cuts off an area of approximately 10% in the upper tail. x = 30 + 8.2(1.28) = 40.50 A stock price of $40.50 or higher will put a company in the top 10% Using Excel: =NORMINV(.9,30,8.2) = 40.51 (you wont have Excel during test, learn to use tables)...
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HW2Solutions - = HYPGEOMDIST(0,5,4,52) = .6588 d. 1 - f (0)...

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