HW3Solutions

HW3Solutions - 5E Fall 2010 Homework 3 Solutions Chapter 7:...

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5E Fall 2010 Homework 3 Solutions Chapter 7: 21. E ( x ) = 1020 x n / / . 100 75 1155 a. 1030 1020 .87 11.55 z P ( z ≤ .87) = .8078 1010 1020 .87 11.55 z   P ( z < -.87) = .1922 probability = .8078 - .1922 =.6156 Using Excel: =NORMDIST(1030,1020,11.55,TRUE)-NORMDIST(1010,1020,11.55,TRUE)=.6134 b. 1040 1020 1.73 11.55 z P ( z ≤ 1.73) = .9582 1000 1020 1.73 11.55 z   P ( z < -1.73) = .0418 probability = .9582 - .0418 = .9164 Using Excel: =NORMDIST(1040,1020,11.55,TRUE)-NORMDIST(1000,1020,11.55,TRUE)=.9167 Chapter 8: 7. Margin of error = .025
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This note was uploaded on 11/25/2010 for the course PSTAT PSTAT 5E taught by Professor Landrigan during the Fall '08 term at UCSB.

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HW3Solutions - 5E Fall 2010 Homework 3 Solutions Chapter 7:...

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