# Lab202 - 1 q1 x0 zy 0 0 Part I E x y z x 1 q 1.y 3 4 π r x...

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Unformatted text preview: 1 q1 x0 zy 0 0 Part I E( x, y , z ) x 1. q 1 .y 3 4 π r( x, y , z) z a1 0 k 0 1 Φ 6.Φ =1 r(xyaz ax y z , ,) Questions: a a q1 1 2 E( x,y ,a2.kd xd y 6.Φ= 1 2) 1. Because, since the charge is in the middle, the field lines cross each side the same way. So the total flux is equal to the flux of one side times 6 since there are six sides. 2. It changes to -1 because now the charge inside is -1. E( x, y , z ) x 1. q 1 .y 4 π r( x, y , z) 3 z 3. It increases by a factor of 2 because the flux is directly proportional to the charge. a Φ a a a E( x,y ,a) .kd xd y 2 4. No it doesn't and it shouldn't because the charge remained the same so the flux, which is directly proportional to the charge, should also stay the same. Part II: 3. 3 4. 5. 6. 7. Because the volume of the shape and distance of the shape are proportional the flux is not affected by their mutual change. ...
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## This note was uploaded on 11/26/2010 for the course PHYSICS 121 taught by Professor Fayngold during the Spring '10 term at NJIT.

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