Lab202 - 1 q1 x0 zy 0 0 Part I E x y z x 1 q 1.y 3 4 π r x...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 q1 x0 zy 0 0 Part I E( x, y , z ) x 1. q 1 .y 3 4 π r( x, y , z) z a1 0 k 0 1 Φ 6.Φ =1 r(xyaz ax y z , ,) Questions: a a q1 1 2 E( x,y ,a2.kd xd y 6.Φ= 1 2) 1. Because, since the charge is in the middle, the field lines cross each side the same way. So the total flux is equal to the flux of one side times 6 since there are six sides. 2. It changes to -1 because now the charge inside is -1. E( x, y , z ) x 1. q 1 .y 4 π r( x, y , z) 3 z 3. It increases by a factor of 2 because the flux is directly proportional to the charge. a Φ a a a E( x,y ,a) .kd xd y 2 4. No it doesn't and it shouldn't because the charge remained the same so the flux, which is directly proportional to the charge, should also stay the same. Part II: 3. 3 4. 5. 6. 7. Because the volume of the shape and distance of the shape are proportional the flux is not affected by their mutual change. ...
View Full Document

This note was uploaded on 11/26/2010 for the course PHYSICS 121 taught by Professor Fayngold during the Spring '10 term at NJIT.

Ask a homework question - tutors are online