2010200AHW1

2010200AHW1 - | Z = 1) = . 9 and P ( Y = 1 | Z = 0) = . 6....

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STAT 200A HWI Problem 1: For a random smoker, let X = 1 if the person smokes cigarette, and X = 0 if this person smokes pipe. Let Y = 1 if this person is healthy, and Y = 0 otherwise. Let Z = 1 if this person is young, and Z = 0 if this person is old. Let us assume that P ( Z = 1) = 1 / 2. P ( X = 1 | Z = 1) = . 8, and P ( X = 1 | Z = 0) = . 3. P ( Y = 1
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Unformatted text preview: | Z = 1) = . 9 and P ( Y = 1 | Z = 0) = . 6. Let us also assume that Y is independent of X given Z . Calculate P ( Y = 1 | X = 1)-P ( Y = 1 | X = 0). Interpret your calculations by counting a population so that a high school student can understand your result. 1...
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