hmwk4b - ME541: Fatigue of Materials Homework 4 Solutions...

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ME541: Fatigue of Materials Homework 4 Solutions 3.1) Assuming that the edge crack is much smaller than the width of the plate allows use of the stress intensity factor, π a F σ K I = where F = 1.12. For the critical condition c Ic I π a ksi 40 1.12 π a σ in ksi 45 K K × = = = = . Solving for a c gives, a c = 0.321 in. 3.4) In this case, the stress, critical crack length, and fracture toughness are known. ....the question is, what is the required F(a/b)? For the lower strength material, = = = = π a F σ in ksi 105 K K Ic I in π 0.2 ksi (130/2) F × Solving for F (a/b) gives F=2.0379. ..... Solving for a/b in the equation for an edge cracked panel (F(a/b) = 1.12-0.231 (a/b) + 10.55 (a/b) 2 - 21.72 (a/b) 3 + 30.39 (a/b) 4 ) gives a/b=0.39 or b=0.512 in. Similarly for the higher strength material, F = 0.8412 which does not occur for the edge cracked panel. Thus for this combination of high stress, low fracture toughness and the specified critical crack size, the higher strength material
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This note was uploaded on 11/28/2010 for the course ENES enes100 taught by Professor Staff during the Spring '10 term at Maryland.

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hmwk4b - ME541: Fatigue of Materials Homework 4 Solutions...

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