Unformatted text preview: ) is 1/ √ 2 = 0.7 of KA. The amplitude of the output is KAM. KAM( ω ) = 8 * 0.7 = 5.6 Ω We know that the phase delay at ωτ = 1 is 45°. (Delay means shifted rightward – wave comes later than the input.) (This makes sense: φ = tan1 ( ωτ ), and if θ = tan1 (1) then tan θ = 1 = sin θ /cos θ , and these are equal at θ = 45°.) (100 pts)...
View
Full
Document
 Spring '10
 staff
 sinusoidal input, resistive temperature sensor

Click to edit the document details