Quiz 9 solutions

Quiz 9 solutions - ) is 1/ 2 = 0.7 of KA. The amplitude of...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Name______________________ Quiz 9 No calculators are permitted for this quiz. 1. Plot the response, versus ω t, of a resistive temperature sensor for which τ = 0.25 seconds and which has a sensitivity of 2 Ω /°C to a sinusoidal input of amplitude 4 °C when ω = 4 rad/sec. ωτ = 0.25 * 4 = 1 KA = 2 Ω /°C * 4 °C = 8 Ω We know that at this point, the amplitude M( ω
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ) is 1/ 2 = 0.7 of KA. The amplitude of the output is KAM. KAM( ) = 8 * 0.7 = 5.6 We know that the phase delay at = 1 is 45. (Delay means shifted rightward wave comes later than the input.) (This makes sense: = -tan-1 ( ), and if = tan-1 (1) then tan = 1 = sin /cos , and these are equal at = 45.) (100 pts)...
View Full Document

Ask a homework question - tutors are online