**preview**has

**blurred**sections. Sign up to view the full version! View Full Document

**Unformatted text preview: **howard (cah3459) ohw19 turner (56705) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A wire carries a current of I = 44 A along the x-axis from x 1 =- 5 cm to x 2 = 1 . 6 cm. I x x P y 1 x 2 Find the magnitude of the resulting mag- netic field at the point r = 4 cm on the y axis. Correct answer: 126 . 785 μ T. Explanation: Let : x 1 =- 5 cm , x 2 = 1 . 6 cm , and r = 4 cm = 0 . 04 m . From the Biot-Savart Law d & B = μ 4 π I d&s × ˆ r r 2 , the magnetic field at a point from a straight line segment is B = μ I 4 π r (cos θ 1- cos θ 2 ) . In this case, θ 1 = arctan y- x 1 = arctan 4 cm- (- 5 cm) = 38 . 6598 , and θ 2 = 180 - arctan y x 2 = 180 - arctan 4 cm 1 . 6 cm = 111 . 801 , so the resultant magnetic field is B = μ I 4 π d (cos θ 1- cos θ 2 ) = μ (44 A) 4 π (0 . 04 m) (cos 38 . 6598 - cos 111 . 801 ) = 126 . 785 μ T . 002 (part 1 of 2) 10.0 points Imagine a very long, uniform wire that has a linear mass density of 0 . 0033 kg / m and that encircles the Earth at its equator. Assume the Earths magnetic dipole mo- ment is aligned with the Earths rotational axis. The Earths magnetic field is cylindri- cally symmetric (like an ideal bar magnetic). The acceleration of gravity is 9 . 8 m / s 2 and the magnetic field of the earth is 9 × 10- 5 T . What is the magnitude of the current in the wire that keeps it levitated just above the ground? Correct answer: 359 . 333 A. Explanation: Let : g = 9 . 8 m / s 2 , B Earth = 9 × 10- 5 T , and μ = 0 . 0033 kg / m . The Earths geographical North pole is a mag- netic South pole and vice versa . The North pole of a compass is attracted to the South magnetic pole of the Earth, the place where Santa Claus lives. The magnetic and gravitational forces must balance. Therefore, it is necessary to have (for unit length of wire) F = I B = μ g I = μ g B = (0 . 0033 kg / m) (9 . 8 m / s 2 ) 9 × 10- 5 T = 359 . 333 A . howard (cah3459) ohw19 turner (56705) 2 003 (part 2 of 2) 10.0 points The current in the wire goes in the 1. same direction as the Earths spinning motion (West to East). correct 2. opposite direction as the Earths spinning motion (East to West). Explanation: Since the Sun rises in the East, the Earth is turning towards the East and the Earths angular velocity is parallel to the Earths axis, pointing from South to North. S N v E F B I v Earth The total force on the wire is zero and the gravitational force is downward (inward), so the magnetic force must be upward (out- ward). If the current goes from West to East, in the same direction as the Earths spinning motion, & I × & B will be vertically upward (out- ward)....

View Full Document