hw 23-solutions

# hw 23-solutions - howard (cah3459) hw 23 turner (56705)...

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howard (cah3459) – hw 23 – turner – (56705) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 of 2) 10.0 points The alternating voltage oF a generator is rep- resented by the equation E = E 0 sin ω t, where E is in volts, E 0 = 230 V, ω = 583 rad / s, and t is in seconds. ±ind the Frequency oF the electric potential E . Correct answer: 92 . 7873 Hz. Explanation: Let : E max = E 0 = 230 V , and ω = 583 rad / s . ω =2 π f f = ω 2 π = 583 rad / s 2 π = 92 . 7873 Hz . 002 (part 2 of 2) 10.0 points ±ind the voltage output oF the source. Correct answer: 162 . 635 V. Explanation: The rms voltage is E rms = E max 2 = 230 V 2 = 162 . 635 V . 003 (part 1 of 2) 10.0 points The maximum potential di²erence across cer- tain heavy-duty appliances is 340 V. The total resistance oF an appliance is 110 Ω. ±ind the rms potential di²erence across the appliance. Correct answer: 240 . 416 V. Explanation: Let : Δ V max = 340 V . Δ V rms = 2 2 Δ V max = Δ V max 2 = 340 V 2 = 240 . 416 V 004 (part 2 of 2) 10.0 points ±ind the rms current in the appliance. Correct answer: 2 . 1856 A. Explanation: Let : R = 110 Ω . Δ V rms = Δ I rms R Δ I rms = Δ V rms R = 240 . 416 V 110 Ω = 2 . 1856 A . 005 (part 1 of 4) 10.0 points In the circuit shown in fgure, E 1 = (40 V) cos 2 πft , f = 270 Hz, E 2 = 6 V, and R = 40 Ω. E 1 = E max cos ωt E max = 40 V E 2 R ±ind the maximum current through the re- sistor. Correct answer: 1 . 15 A. Explanation: Let : R = 40 Ω , E 1 = (40 V) cos 2 π f t, and E 2 = 6 V .

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howard (cah3459) – hw 23 – turner – (56705) 2 Applying Kirchhof’s loop rule, we have E 1 + E 2 - IR =0 , so the current is I ( t )= E 1 + E 2 R = I 1 cos 2 π f t + I 2 , where I 1 = 40 V 40 Ω = 1 A , and I 2 = 6V 40 Ω =0 . 15 A , since the maximum current occurs when
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## This note was uploaded on 11/28/2010 for the course PHY 56705 taught by Professor Turner during the Spring '10 term at University of Texas at Austin.

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hw 23-solutions - howard (cah3459) hw 23 turner (56705)...

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