HW26Sol - Platt, David Homework 26 Due: Nov 9 2005, 4:00 am...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Platt, David Homework 26 Due: Nov 9 2005, 4:00 am Inst: Ken Shih 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 3) 10 points An effective AC voltage of 145 V at 60 Hz is applied to an RLC circuit with 27 . 4 mH inductor, 0 . 52 F capacitor, and 45 resistor in series. 27 . 4 mH 45 145 V S . 52 F I What is the effective current? Correct answer: 0 . 0284817 A. Explanation: Let : V = 145 V , f = 60 Hz , C = 0 . 52 F = 5 . 2 10- 7 F , L = 27 . 4 mH = 0 . 0274 H , and R = 45 . For an RLC series circuit at f = 60 Hz, X L = 2 f L = 2 (60 Hz) (0 . 0274 H) = 10 . 3296 , and X C = 1 2 f C = 1 2 (60 Hz) (5 . 2 10- 7 F) = 5101 . 12 , so the total impedance is Z = R 2 + ( X L- X C ) 2 = (45 ) 2 + (10 . 3296 )- (5101 . 12 ) 2 1 / 2 = 5090 . 99 ....
View Full Document

Page1 / 3

HW26Sol - Platt, David Homework 26 Due: Nov 9 2005, 4:00 am...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online