hw6_solutions - ES330 Assignment 6 Solutions Chapter 5 Due...

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Unformatted text preview: ES330 Assignment 6 Solutions Chapter 5 Due Date: Thursday October 14, 2010 I Problem 1 A glass manometer with mercury as a working fluid is connected to a duct as shown. Will the mercury in the manometer move as shown in ( a ) or ( b )? Why? Solution We can find the solution by looking at the Bernoulli Equation, assuming the flow is in- compressible, steady, and inviscid. The flow is moving from a larger to a smaller diameter, meaning that the velocity increases from the inlet to the outlet ( V 1 < V 2 ). The Bernoulli Equation in this situation becomes: P 1 + V 2 1 2 + gz 1 = P 2 + V 2 2 2 + gz 2 (1) P 1 + V 2 1 2 = P 2 + V 2 2 2 = constant (2) Therefore, if the velocity is greater at the outlet than the inlet, the pressure will be less at the outlet than the inlet: P 2 < P 1 (3) This pressure difference is represented by figure ( a ). Figure( a ) 1 II Problem 2 An aircraft flies at an altitude of 6,000 m . A static probe is used to measure the velocity. If the probe reads a differential pressure of 3 kPa , determine the velocity of the aircraft. Solution We can use the Bernoulli Equation to solve this problem. We assume that the entrance of the probe is point one and the stagnation point of the probe is point 2. Therefore, in Equation 1, V 2 = 0 and z 1 = z 2 . Solving for V 1 , we get: V 1 = s 2 P (4) Using the density of air at different elevations table from the appendix of the text, the...
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This note was uploaded on 11/29/2010 for the course ME 330 taught by Professor Bohl during the Fall '10 term at Clarkson University .

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hw6_solutions - ES330 Assignment 6 Solutions Chapter 5 Due...

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