oldhomework 07-solutions

# oldhomework 07-solutions - Reilly(mar3978 oldhomework 07...

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Reilly (mar3978) – oldhomework 07 – Turner – (56725) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points A point charge q 1 is concentric with two spher- ical conducting thick shells, as shown in the figure below. The smaller spherical conduct- ing shell has a net charge of q 2 and the larger spherical conducting shell has a net charge of q 3 . q 3 q 2 q 1 R 1 R 2 R 3 R 4 R 5 r 1 r 2 r 3 r 4 Hint: Under static conditions, the charge on a conductor resides on the surface of the conductor. What is the charge Q r 1 on the inner surface of the smaller spherical conducting shell? 1. Q r 1 = + q 1 2. Q r 1 = 0 3. Q r 1 = - q 1 - q 2 4. Q r 1 = - q 1 - q 2 - q 3 5. Q r 1 = - q 1 + q 2 + q 3 6. Q r 1 = - q 1 correct 7. Q r 1 = - q 1 + q 2 8. Q r 1 = + q 1 - q 2 9. Q r 1 = + q 1 + q 2 + q 3 10. Q r 1 = + q 1 + q 2 Explanation: Basic Concept: Under static conditions, the electric field inside a conductor is zero. Charge is conserved, neither created or dis- troyed. Solution: The net charge inside a Gaus- sian surface located at r = R 2 must be zero, since the field in the conductor must be zero. Therefore, the charge on the inner surface of the smaller spherical conducting shell must be - q 1 . 002 (part 2 of 4) 10.0 points What is the charge Q r 2 on the outer surface of the smaller spherical conducting shell? 1. Q r 2 = - q 1 + q 2 2. Q r 2 = + q 1 + q 2 - q 3 3. Q r 2 = 0 4. Q r 2 = + q 1 - q 2 5. Q r 2 = + q 1 6. Q r 2 = + q 1 + q 2 + q 3 7. Q r 2 = + q 1 + q 2 correct 8. Q r 2 = - q 1 - q 2 9. Q r 2 = - q 1 - q 2 - q 3 10. Q r 2 = - q 1 Explanation: The net charge inside a Gaussian surface located at r = R 3 must be q 1 + q 2 , since charge is conserved. Therefore, the charge on the outer surface of the smaller spherical conducting shell must be q 1 + q 2 . 003 (part 3 of 4) 10.0 points What is the charge Q r 3 on the inner surface

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