JIM101_VC1_2010-2011_Solutions - PUSAT PENGAJIAN PENDIDIKAN...

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PUSAT PENGAJIAN PENDIDIKAN JARAK JAUH UNIVERSITI SAINS MALAYSIA SIDANG AKADEMIK 2010/2011 JIM101 – CALCULUS SOLUTIONS – VIDEO CONFERENCE 1 MUHAMAD FUAD ABDULLAH Answers 1. Solve the following inequalities (a) 3 2 + x x 0 2 1 0 2 3 0 3 2 0 3 2 2 2 - - + - - + - + x x x x x x x x x x x ) )( ( Critical points are x = 0 , x = 1 and x = 2 x < 0 0 < x < 1 1 < x < 2 x > 2 x + + + x – 1 + + x – 2 + x x x ) )( ( 2 1 - - + + 0 2 1 - - x x x ) )( ( must be 0 or negative, thus the answer is x < 0 and 1 ≤ x ≤ 2 or in the interval notation as ( 29 [ ] 2 1 0 , , -
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2 1 - x x 0 1 2 0 1 2 2 0 2 1 - - - + - - - x x x x x x x Critical points are x = 1 and x = 2 x < 1 1 < x < 2 x > 2 x – 1 + + 2 – x + + 1 2 - - x x + 0 1 2 - - x x must be 0 or negative, thus the answer is x <1 and x ≥ 2 or in the interval notation as ( 29 [ 29 - , , 2 1 2. Find all values of x for 0 1 2 3 2 = + - x x i x 3 2 3 1 6 1 2 2 6 2 6 1 2 2 2 6 1
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This note was uploaded on 12/01/2010 for the course SUKAN md taught by Professor Saipon during the Spring '10 term at Albany College of Pharmacy and Health Sciences.

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JIM101_VC1_2010-2011_Solutions - PUSAT PENGAJIAN PENDIDIKAN...

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