3AL Lecture 10 - (ddd) Successive Application of the N + 1...

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Complex Coupling singlet triplet doublet quartet ?
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Successive Application of the N + 1 Rule What if: J AB = 3 Hz J AC = 8 Hz J BC = 6 Hz doublet of doublets (dd) doublet of doublets (dd) doublet of doublets (dd) Two different hydrogen atoms coupling to a third hydrogen atom
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Successive Application of the N + 1 Rule What if: J AB = 6 Hz J AC = 6 Hz J BC = 8 Hz doublet of doublets (dd) doublet of doublets (dd) doublet of doublets (dd) Two different hydrogen atoms coupling to a third hydrogen atom
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Successive Application of the N + 1 Rule Doublet of Quartets (dq)
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doublet of doublet of doublets (ddd) doublet of doublet of doublets
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Unformatted text preview: (ddd) Successive Application of the N + 1 Rule Three different hydrogen atoms coupling to a fourth hydrogen atom Predicted (dq) (t) (broad singlet) Observed (t) (q) Spin-Spin Coupling with Hydrogen Atoms Attached to Heteroatoms Ethanol Proton exchange is fast relative to the NMR time scale (t) J = 2.5 Hz = 2.5 Hz = 7.3 Hz = 7.3 Hz integral 1 2 3 2 Count carbons: 4 Unique resonances: 9.8 ( 1 H), 200( 13 C) (t, = 2.5) 4.5 ppm (d, = 2.5) H B H A H D H C A B C D Determining a Structure From NMR A B C D CHCl 3 7.27 ppm CDCl 3 77.0 ppm...
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3AL Lecture 10 - (ddd) Successive Application of the N + 1...

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