Group3II - N which is bijective because g is bijective....

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II. Let A be a countable set, B a subset of A and B is not finite. Prove that B is countable. A is countable. There exists a bijective function f : N A. there exists a function g : A N If you restrict the domain of g to B, then you get a new function h : B
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Unformatted text preview: N which is bijective because g is bijective. there exists a function bijective function j : N B, which means B is countable....
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This note was uploaded on 11/29/2010 for the course CSC 873569 taught by Professor Roberts during the Spring '10 term at ASU.

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