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Unformatted text preview: BCH 451 Summer 2005 Exam #3 NAME (3) A = -D-galactosyl (1-4) -D-ribulofuranose; B = -D-glucosyl (1-4) -D-xylulofuranose pH = 7 (3) C = 1-stearoyl-2-oleoyl phosphatidyl choline; D = 1- palmitolyl-2-palmitoleoyl phosphatidyl ethanolamine pH = 7 (3) F = pAppdCp; G = pGpddUpp pH = 7 [Draw purines in anti and pyrimidines in syn conformations] 1. For the following coenzyme B = biotin; T = tetrahydrofolate, give: a. (0.2) the vitamin name [or state none if none] b. (0.2) co-substrate or prosthetic group [circle correct answer] c. (0.5) major metabolic role(s): d. (0.5) diagram of active [red] portion [include Hs and Rs]: 2. For M = mRNA; T = tRNA a. (1) What is its full name and size range? b. (1.5) What is its function? c. (1) How does it fit into the central dogma? [start your answer by stating the central dogma and then indicate where in this scheme your RNA molecule fits in.] 3. (3) Puzzler The following is a quote from your text book [p. 701]: TRNA plays an important role in interpretingThe following is a quote from your text book [p....
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This note was uploaded on 12/01/2010 for the course BCH 451 taught by Professor Knopp during the Spring '08 term at N.C. State.
- Spring '08