17 - BCH 451 Summer 2005 Exam #3 NAME (3) A = -D-galactosyl...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: BCH 451 Summer 2005 Exam #3 NAME (3) A = -D-galactosyl (1-4) -D-ribulofuranose; B = -D-glucosyl (1-4) -D-xylulofuranose pH = 7 (3) C = 1-stearoyl-2-oleoyl phosphatidyl choline; D = 1- palmitolyl-2-palmitoleoyl phosphatidyl ethanolamine pH = 7 (3) F = pAppdCp; G = pGpddUpp pH = 7 [Draw purines in anti and pyrimidines in syn conformations] 1. For the following coenzyme B = biotin; T = tetrahydrofolate, give: a. (0.2) the vitamin name [or state none if none] b. (0.2) co-substrate or prosthetic group [circle correct answer] c. (0.5) major metabolic role(s): d. (0.5) diagram of active [red] portion [include Hs and Rs]: 2. For M = mRNA; T = tRNA a. (1) What is its full name and size range? b. (1.5) What is its function? c. (1) How does it fit into the central dogma? [start your answer by stating the central dogma and then indicate where in this scheme your RNA molecule fits in.] 3. (3) Puzzler The following is a quote from your text book [p. 701]: TRNA plays an important role in interpretingThe following is a quote from your text book [p....
View Full Document

This note was uploaded on 12/01/2010 for the course BCH 451 taught by Professor Knopp during the Spring '08 term at N.C. State.

Page1 / 2

17 - BCH 451 Summer 2005 Exam #3 NAME (3) A = -D-galactosyl...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online