P219lecture18multilenses

P219lecture18multilenses - Goal: To understand multiple...

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Goal: To understand multiple lens systems. Objectives: 1) To understand how to calculate values for 2 lens combos 2) To understand the human eye
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2 lenses We have learned how to do the equations for the first lens, but what happens when you have 2 lenses? The image from the first lens becomes the object for the second lens. The separation distance between lenses is denoted as s. Everything is normal after that. So, 1/p2 + 1/q2 = 1/f2 And p2 = s – q1 The final image type is determined by the 2 nd lens.
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Sample Lets make sure we still know the lesson from yesterday… You have 2 lenses. We will do the 2 nd lens in the 2 nd sample. An object is 10 cm from lens one. The focal length is 3 cm. What is the image distance (i.e. q1)?
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Sample 2 1/p2 + 1/q2 = 1/f2 And p2 = s – q1 For the previous question, if the separation distance between lenses is 20 cm then what is p2?
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Sample 3 Now that we have p2 as 15.7 cm, if the focal length for the 2 nd lens is 10 cm then what is the image distance for the 2 nd lens?
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Magnification Each lens will have a magnification. How do you think this will work with 2 lenses? A) M = M1 + M2 B) M = M1 – M2 C) M = M1 * M2 D) M = M1 / M2
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Sample We will put all this together… We have 2 lenses.
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This note was uploaded on 12/01/2010 for the course PHYSICS 21900 taught by Professor Rhoads during the Spring '10 term at IUPUI.

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P219lecture18multilenses - Goal: To understand multiple...

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