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Unformatted text preview: white (rw22679) – Hw02 – Ross – (10219) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points An ion accelerated through a potential dif- ference of 138 V experiences an increase in kinetic energy of 4 . 27 × 10- 17 J. Find the magnitude of the charge on the ion. Correct answer: 3 . 0942 × 10- 19 C. Explanation: Let : Δ V = 138 V and K = 4 . 27 × 10- 17 J . By conservation of energy Δ K =- q Δ V q =- Δ K Δ V =- 4 . 27 × 10- 17 J 138 V =- 3 . 0942 × 10- 19 C , which has a magnitude of 3 . 0942 × 10- 19 C . 002 (part 1 of 3) 10.0 points A pair of oppositely charged parallel plates are separated by 5 . 59 mm. A potential difference of 570 V exists between the plates. What is the strength of the electric field between the plates? Correct answer: 1 . 01968 × 10 5 V / m. Explanation: Let : Δ V = 570 V and Δ d = 5 . 59 mm = 0 . 00559 m . The potential difference is Δ V =- E Δ d E =- Δ V Δ d =- 570 V . 00559 m =- 1 . 01968 × 10 5 V / m . which has a strength of 1 . 01968 × 10 5 V / m . 003 (part 2 of 3) 10.0 points What is the magnitude of the force on an electron between the plates? Correct answer: 1 . 63148 × 10- 14 N. Explanation: Let : q =- 1 . 60 × 10- 19 C . The electric force is F elec = q E =- ( 1 . 60 × 10- 19 C ) (1 . 01968 × 10 5 V / m) =- 1 . 63148 × 10- 14 N , with a magnitude of 1 . 63148 × 10- 14 N ....
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This note was uploaded on 12/01/2010 for the course PHYSICS 21900 taught by Professor Rhoads during the Spring '10 term at IUPUI.

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Solution2_pdf - white(rw22679 – Hw02 – Ross –(10219 1 This print-out should have 13 questions Multiple-choice questions may continue on the

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