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This printout should have 19 questions.
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001
10.0 points
A long solenoid carries a current 30 A.
Another coil (oF larger diameter than the
solenoid) is coaxial with the center oF the
solenoid, as in the fgure below.
The permeability oF Free space is 4
π
×
10
−
7
N
/
A
2
.
8 m
1 m
Outside solenoid has 270 turns
Inside solenoid has 4650 turns
14
.
1 cm
4
.
1 cm
±ind the mutual inductance oF the system.
Correct answer: 0
.
00104149 H.
Explanation:
ℓ
2
ℓ
1
Outside solenoid has
N
1
turns
Inside solenoid has
N
2
turns
A
1
A
2
Let :
r
1
= 14
.
1 cm = 0
.
141 m
,
r
2
= 4
.
1 cm = 0
.
041 m
,
N
1
= 270
,
N
2
= 4650
,
ℓ
1
= 1 m
,
ℓ
2
= 8 m
,
n
1
=
N
1
ℓ
1
= 270 turns
/
meter
,
n
2
=
N
1
ℓ
1
= 581
.
25 turns
/
meter
,
I
2
= 30 A
,
and
μ
0
= 4
π
×
10
−
7
N
/
A
2
.
M
is the mutual inductance
A
1
=
πr
1
2
=
π
(0
.
141 m)
2
= 0
.
062458 m
2
A
2
=
πr
2
2
=
π
(0
.
041 m)
2
= 0
.
00528102 m
2
B
2
=
μ
0
N
2
I
2
ℓ
2
The ²ux Φ
12
through coil 1 due to coil 2 is
Φ
12
=
B
2
A
2
.
Thus, the mutual inductance is
M
=
N
2
Φ
12
I
1
=
N
1
Φ
21
I
2
=
μ
0
N
1
N
2
A
2
I
2
ℓ
2
I
2
=
μ
0
N
1
N
2
A
2
ℓ
2
= (4
π
×
10
−
7
N
/
A
2
)
(270)(4650)
8 m
×
(0
.
00528102 m
2
)
=
0
.
00104149 H
.
002
10.0 points
A certain capacitor in a circuit has a capaci
tive reactance oF 41
.
5 Ω when the Frequency is
103 Hz.
What capacitive reactance does the capac
itor have at a Frequency oF 10400 Hz?
Correct answer: 0
.
41101 Ω.
Explanation:
Let :
X
C
= 41
.
5 Ω
,
f
low
= 103 Hz
,
and
f
high
= 10400 Hz
.
The capacitive reactance is
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This note was uploaded on 12/01/2010 for the course PHYSICS 21900 taught by Professor Rhoads during the Spring '10 term at IUPUI.
 Spring '10
 Rhoads
 Physics, Current

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