171hw1solutions

171hw1solutions - Question 6 For n =4, l=2 thus m l = 2, 1,...

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CHEM 171 Fall 2010 Solution Key for Homework 1 Question 1 Students are responsible for exceptions due to ½ and fully filled shell stability. Cr [Ar]3d 5 4s 1 Cu [Ar]3d 10 4s 1 Mo [Kr]4d 5 5s 1 Pd [Kr]4d 10 Ag [Kr]4d 10 5s 1 Au [Xe]4f 14 5d 10 6s 1 Question 2 A excited B forbidden C ground D excited E excited F forbidden Question 3 P 1s 2 2s 2 2p 6 3s 2 3p x 1 3p y 1 3p z 1 Na 1s 2 2s 2 2p 6 3s 1 As 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p x 1 4p y 1 4p z 1 C - 1s 2 2s 2 2p x 1 2p y 1 2p z 1 O + 1s 2 2s 2 2p x 1 2p y 1 2p z 1 Question 4 Fluorine: 1s 2 2s 2 2p x 2 2p y 2 2p z 1 (1 unpaired electrons) Silicon: 1s 2 2s 2 2p 6 3s 2 3p x 1 3p y 1 (2 unpaired electrons) Neon: 1s 2 2s 2 2p 6 (0 unpaired electrons)
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Unformatted text preview: Question 6 For n =4, l=2 thus m l = 2, 1, 0, -1, -2 (5 possible values) Question 7 Sr [Kr]5s 2 Ca 2+ [Ar] or 1s 2 2s 2 2p 6 3s 2 3p 6 Question 8 Answer: In the Hydrogen atom (z=1) there are no effects from shielding or e-/e- repulsion as in many e- atoms. Bonus For this particular key the lowest value of n =3, but if you started with n=2 then its also correct. Given the following set of rules: Noble Gases 2, 6, 12, 20 Halogens 5, 11, 19...
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171hw1solutions - Question 6 For n =4, l=2 thus m l = 2, 1,...

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