W06 MT1 - CHEMISTRY 110A 1N STR: R.N. SCHWARTZ MIDTERM...

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Unformatted text preview: CHEMISTRY 110A 1N STR: R.N. SCHWARTZ MIDTERM EXAlVI #1 Fri day, February 3, 2006 NAME: SID # (la Instructions.- 1. This exam consists of 3 questions. Before starting, write your name on every page. 2. Indicate answers, including units, and show your method of calculation and reasoning. I I I I 3. No credit will be given for an answer alone or for an illegible answer. 4. Use the conventions for significant figures and units. 5‘ If you run out of space working a problem, use the back of that page and indicate on the front that you have done so 6. You may use a calculator. No books or notes. 7. Useful constants and equations are on last page; you can carefully detach this page. MAKE SURE YOUR EXAM HAS 7 NUMBERED PAGES. V CHEM 110A MIDTERM #1 3 February 2006 NAME- 1. (40p0ints) One mole o .v v c 41"” 3. Calculate the work w for each step. v,_ P 3 3+0? A: W: —y\¥~.T\Y\-\7" : - HRT‘Y) $3: :_@)(8,314X300)M—i W =’4.0 KT 3+W152TL:300K)59+ mm is T97. —. _7—-~h__” a 8 8,314 , l /Cv $00K é 3331‘] R T10 12H? 1‘9: 48“! K w = @wo\)L%R)(13q .5500) = ~43} \<:r 6W 0»: w: —\oAV, bch u)er u (y? men M49 B, _ (Amwaozsswxq \4) V‘ ‘- 0403 bar w: {ow aha-mm): +40%L 19am 2 = Hour—Hy CHENI 110A MIDTERM #1 3 February 2006 NAME: amply. w=o Wk Ave—O Wm= —4 «4.38M.qu = —- 4.33 HI b. What is the value of AU and AH for the overall sequence of steps? Be sure to justify answer. ll“: is 5; 045411060 DU=0H=O c. What is the value of q for the overall sequence? since DUPO) \U = ‘5), CHEM 110A MIDTERM #1 3 February 2006 NAME: 2. (30 points) 3. Given that dz; = C V dT + + P]dV , prove that multiplying dé by J/T leads to an 7' 8V exact differential expansion. An ideal gas equation of state may be used for the proof. 9“ 3% ., erat + 4‘: Wlfil’lév 2.9: ’0 9V TT gw;%fi§ ‘0 \/ liegl‘aTlT " 3T v V CHEM 110A MIDTERM #1 . 3 February 2006 NAME: b. Derive an expression for the change in the internal energy, AU , of a van der Waals gas undergoing a reversible isothermal expansion from an initial volume V1 to a final volume V2. AU: CHEM 110A MIDTERM #1 3 February 2006 NANIE: 3. (30 points) One mole of steam at 1000C and 1 bar is transformed to ice at 00C and 1 bar. Calculate AH for this process. For H20 : C0 = 33.58 JK‘lmol'l, ngmyliq = 75.3 JK”m0['1 , P,In.g C? m = 37 .65 JK‘lmol“, AH}; = 6.008 kJ mol_1 and AHfap = 40.65 1d marl. p= (bar T7373 Yr; 4m0\ YMQDQ, ‘— 3M 50M: AH4+AHL+ 503 0 3 9H1: AHWMSAHM: “(A W°‘>C"*0.l05¥40 > AHL = (4m) (was) (223 ~ 313) -— — 1550 5‘5 " [mammary = {Amonwozfi : — (000% 3- Afiv’r ‘3 - 54.3 KT END OF THE END 6 ...
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This note was uploaded on 04/03/2008 for the course CHEM 110A taught by Professor Schwartz during the Winter '06 term at UCLA.

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W06 MT1 - CHEMISTRY 110A 1N STR: R.N. SCHWARTZ MIDTERM...

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