2Bsection5_6part1

# 2Bsection5_6part1 - A r e a b e tw e e n 2 c u r v e s S e...

This preview shows pages 1–8. Sign up to view the full content.

Area between 2 curves. Section 5.6 Part 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
upper function lower function PROBLEM 1 Given 2 functions of x: y=f(x) and y=g(x), defined over [a,b], find the area of the region enclosed between the 2 graphs. ANSWER right‐most value of x left‐most value of x A=?
Areas between 2 functions as Riemann Sum: The height of a rectangle is of the form f(x)‐g(x), where f is the upper curve, and g is the lower one.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Right function Left function PROBLEM 2 Given 2 functions of y: x=f(y) and x=g(y), defined over [c,d], find the area of the region enclosed between the 2 graphs. ANSWER biggest value of y smallest value of y A=?
Right function: x=f(y) left function: x=g(y) We use horizontal rectangles. The height of a rectange is f(y)‐g(y), where f is the right curve and f is the left one.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
? ? You need the graphs!
upper function lower function Look at the graph ? ? ? What about a and b? They are the x‐coordinates of the points where the 2 curves intersect.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern