08samplefinal soln

08samplefinal soln - Math 54 — Sample Final Exam...

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Unformatted text preview: Math 54 — Sample Final Exam August 15, 2008, 08:00—10:00 Name: \v i on This is a closed book, closed notes exam. Calculators are not allowed. You have two hours to complete the exam. To receive full credit, write legibly, show your work and write proofs in complete sentences. If you need more space, use the back of the page of the problem on which you are working. —-— 1. Find the solution of the initial—value problem 2y” + 99, + 10y = 8sint + QCost 31(0) = 4, y’(0) = —6. 30 (K— “2:1, (3.: ‘%§7,) So '“xe 8%“qu sakfi-‘M 0% ‘HQ \Avwswoos eflu «\wm‘ x' 5 ---1t Q 9: it 3%) "' C‘ e “' 1 . Sway? N2 053m C1:"1‘Q\$CQ. mm _\.\A€ $o\o¥\m 09V OuC \NkA“ \Jo~\UQ ‘3“)me { 5 5 at w» = SW; ~16!” + C33 B3 \n3YEC\\vvx D, is om QESQMcAue 03? 4%: mfifix (mi cm) W s is case a.“ “GM“ (mummy owl $0 9. we}: ‘02 AM \uéc exfiwduz (“PM 1). We. weak He eéxmsymus o‘ SW D E “SM R E Wm 3. Find a general solution for the ODE 4y(5) + 831(4) + 53/" + 4y" + 83/ + 53/ = 0. (Hint: the function y(t) = 6“ sin(%) is one solution.) Wm M Ckuwéfitfiév‘xc ea‘uckm is *6“: $vfi+5v3 4 43+ (Zn Jr 5 3 O TMQ \Am)‘ fife/“S \)$ ‘A‘MAJY r: “\tib OWQ No SOUH‘DAS- \A‘uwz (C— Phi \“k —-(-\ 2.‘\\ 2 CL +1v + 5 SkoAA he °~ guests? DQ “\\~Q 4. Find the solution of the heat flow problem 3U 82’“- 8—t($’ 0:87;: (0<a:<7r,t>0) M015): u,=(7rt) 0 (t>0) “($70)=€_x (0<x<7r) “Q SUMO“ So\0'\'\o~f\ ogg JANE £ch AMa “ABS iS" -n‘rl', _ (mm): 2: one who , OT ‘0 36: {Cd 80 Arm ’M‘L OX 6 , wc amok CW: %S:E Q—XS‘mLHQ A1. =—-,—%[ a \ *— {zwq o 1 K91: I ”x .. l - “X 3 «M - 8N9, WNW] — E. R» D + “e to (. \Xw I o a " 'L 1‘ '. ‘n V\K\AK,B .. 3‘an «“Q“L'\\n " “ go e’ S L “ 7K - “ m ”W" ~ “mom - Q [C 9- ( \ _ Zn _ ”‘1‘ _\ n TMOS Cw mix“ 6 ”7 wt 5. Find the formal solution of the problem (92H 8%; 5;($ay)+53§($7y)=0 (0<:v<7r,0<y<1) U(0,y) =U(7r,y) = 0 (0 < y <1) %3($70)=03 ”($21):f($) (0<£D<7T) We use swwfi‘m .Q miésvs = Mx® =Xm\{L3\) fig ‘m’w ?DE‘ X” Y+ XY” = O ) Adds :9er £31."; \< M xwvxm =0, \(I(0\=O. X 3 Tye 0N; $0: X is {[email protected]“ \<X :0 mm, o u ‘ XW: CS‘VQ (0X\ wkiéx \/\0»$ 3% \ S\)W"\ X‘ a (V O ‘S;(X\ 2 E C“ (03‘ k“) 8““k“x\ ) C“: .33...“ ‘ nu ‘ ncush n O 6. Let A be a square matrix, and let p be the characteristic polynomial of A. (a) If q is a polynomial such that q(A) = 0, show that q(/\) = 0 for. each eigenvalue A of A. (b) Show that if A is diagonalizable then p(A) = 0. (M Svmsose «limit A is on eiaemwxoc 0Q Q . ...
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