This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: CHEMISTRY 110A INSTR: RN. SCHWARTZ MIDTERM EXAM #1 Friday, October 28, 2005 NAME: SID # ‘ (last) (ﬁrst) ‘
Instructions:
 1. This exam consists of 3 questions. Before
starting, write your name on every page. 2. Indicate answers, including units, and show
your method of calculation and reasoning. 3. No credit will be given for an answer alone
or for an illegible answer. 4. Use the conventions for signiﬁcant ﬁgures
and units.
5. If you run out of space working a problem, use the back of that page and indicate on the
from that you have done so 6. You may use a calculator. No books or notes. 7. Useful constants and equations are on last page;
you can carefully detach this page. MAKE SURE YOUR EXAM HAS 8 NUMBERED PAGES. CHEM 110A MIDTERM #1 28 October 2005 NAME: 1. (35 points) One mole of an ideal monatomic gas in its initial state T, = 25 "C and Vi = 5.00 L is
subjected to the following sequence of steps: A) It is heated at constant volume from 25 “C to 100 “C.
B) It is expanded ﬁeely into a vacuum (Jouletype experiment) to double its volume.
C) It is cooled 'ifeversibly at constant pressure 0% bar to 25 "C and a
ﬁnal volume of 5.00 L. Ergo Calculate in Joules q, w, AU , and AH for the overall process A + B + C. cw AUJL‘ 95 A ~— a» I \_ f z 11} J
1  ﬂ " (A ' Milh I
l L '2, J L s I 1' . I —
.7 \ 7 L" A ‘r “ ,_. 7 h
Ugo Vi Ltd F “ i ‘ W K L.» " QC) LJ " L L "190 I ‘ t, .
J '7 CHEM 110A MIDTERM #1 28 October 2005 NAME: CHEM 1 1 0A MIDTERM #1 28 October 2005 NAME: 2. (3 0 points) One mole of hydrogen gas at 25.0 “C and 1.00 bar is compressed adiabatically and
reversibly into a volume of 5.00 L. Assuming ideal gas behavior, calculate a) the
ﬁnal temperame, b) the ﬁnal pressure, and c) the work done on the gas. (a5 du? CV Ch ‘t (c) \.. dv Jr $04.:
(ill; “jug : *Odv UmugﬁoHB
LO 0 Gd'UW'L
cm: Mu: —:{’7~Tav ' Cw“ U; ’H a  ~13  9%w%%mw»m%mQMQ vi; ,1 CHEM 110A MDTERM #1 2.8 October 2005 NANIE:
95 ad. anLJr.‘ L C\ Au: 915+Aw
AU h): 5/; ‘OR (TngJB ma. S/Q “(NAB (8 SNI/md‘és (9 (ﬁg7 ’ 72%;) Sam: CHEM 110A NIIDTERM #1 28 October 2005 NAM: 3. (35 points) A gas obeys the equation of state PV = nRT[1+ a IV]; where a is a constant. a) If P = P(T, V), what is the total diﬁ‘erential dP? b) Show that dP is an exact differential and
c) Derive expressions for w and AU for a reversible isothermal expansion from an initial
state with volume V; to a ﬁnal state with volume V2. V Vi
3.7 r‘._ \IL K (GT \JVCX T+ ( /0\J )T
(00/ T“ _ (g): n (F I ; “(i “L 520$
C) )U (91— \ V “"7; If} jg. \1 V1
0) Q I .. \
(W J A n" T,“ oiD’g—l' ‘ ._  “ONT gawkT
r cw v Vljt — _____a _ a?“
)T V VI
4&0: + B T “t” ’16? Boxr V \/ V3
2
“A it 5):: ‘ 53—f— Amn emu, Moet
("Jr()4 aqbvf K
C): (a ﬂame} “_ of.“ ’ gig—(1r) :2“ gang
if“ : (3’4 ‘ 1 7“ Va a: 2 ’ ‘7:
New d" C )t A, 9T M v v I
NJ Law am)? (awxv 913': ZIP£2" 'l , 9, f 2 .. _ ‘1:
\I‘  7% CHEM 110A WDTERM #‘1 28 October 2005 NAME: aw: Ipdxj  Caugblua. ’3 ._ “RT . C a “BET I.
{Ax—Sde 37c“ 3 mad!
\Sbwf‘mﬂ :§ Cang¥MdT w. r rm SLOW —omm END OF THE END I Some useful equations and values of fundamental constants R = 8.31451 JK’ mor’ = 00820568 1. atm K" me!" = 0.0831451 L bar K" mor’, 1 L bar = 100 J, 1 L arm, = 101.325 J, N, = 6.02214x 1023 particlesmart 1L = dm’, For f(x)=xa: d%x=asxa_l, Ixﬂdx=xn+1fn+L Jx_ldx=lnx, dfnx=d%, d. 1
30131.80). ewe/31, CF 2 (ﬁr/ﬂL’ (wag/L = T(817§T)V ‘P' ((3%;ch = V ‘TPVarL Tr 77]— pVV =constant, 7 = CP,m ’ICV.m‘[ V—b "I V2 "I 2
PV=nRT, (PM? %2](V—nb)=nRT,[P+ a )1 : _Rs CPJH : R,
2 For an ideal monaromic gas: C yam 3 5 7' For an ideal diatomic gas: Cpl,“ = 3R , CE," = E R , Foran ideal gas: Cpm — Cy‘m = R . ...
View
Full Document
 Fall '06
 Schwartz

Click to edit the document details