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Unformatted text preview: schroeder (cs39963) Quiz 1: Units, Dimensions, Conversions Balasubramanya (1401310) 1 This printout should have 22 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. This is your first quiz for credit. 001 10.0 points One tenth (0.1) of a meter is called a 1. decimeter. correct 2. dekameter. 3. centimeter. 4. millimeter. Explanation: 002 10.0 points A flat circular plate of copper has a radius of . 268 m and a mass of 40 . 3 kg. What is the thickness of the plate? Correct answer: 0 . 0200002 m. Explanation: Let : m = 40 . 3 kg and r = 0 . 268 m . The density of copper is = 8 . 93 10 3 kg / m 3 . = m V , for a flat circular plate, so V = r 2 h = m h = m ( r 2 ) = 40 . 3 kg (8930 kg / m 3 ) (0 . 268 m) 2 = . 0200002 m . 003 10.0 points Consider a cube of soft, spongy material. Which piece below has the larger density? 1. Densities are the same. 2. Unable to determine 3. cutting out a piece of the cube that has oneeighth the volume 4. compressing the cube until it has one eighth the volume correct Explanation: 1 = m V Compressing the cube results in a denser ma terial. Compared to the piece cut out, the compressed piece has density 2 = m 1 8 V = 8 m V = 8 1 . 004 10.0 points A piece of wire has a density of 5 . 5 g / cm. What is the mass of 10 . 6 cm of the wire? Correct answer: 58 . 3 g. Explanation: Let : = 5 . 5 g / cm and = 10 . 6 cm . This is a linear mass density: = m m = = (5 . 5 g / cm) (10 . 6 cm) = 58 . 3 g . schroeder (cs39963) Quiz 1: Units, Dimensions, Conversions Balasubramanya (1401310) 2 005 (part 1 of 2) 10.0 points Consider two planets with uniform mass dis tributions. The mass density and the radius of planet 1 are 1 and R 1 , respectively, and those of planet 2 are 2 and R 2 What is the ratio M 1 M 2 of their masses? 1. M 1 M 2 = parenleftbigg 2 1 parenrightbiggparenleftbigg R 1 R 2 parenrightbigg 2 2. M 1 M 2 = parenleftbigg 1 2 parenrightbiggparenleftbigg R 2 R 1 parenrightbigg 3 3. M 1 M 2 = parenleftbigg 2 1 parenrightbiggparenleftbigg R 1 R 2 parenrightbigg 4. M 1 M 2 = parenleftbigg 1 2 parenrightbiggparenleftbigg R 2 R 1 parenrightbigg 2 5....
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 Fall '08
 STAFF
 Physics

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