Quiz 4 Solutions - schroeder (cs39963) Quiz 4: Two...

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Unformatted text preview: schroeder (cs39963) Quiz 4: Two Dimensional Motion - Projectile and Circular Moton balasubraman This print-out should have 31 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A projectile is fired straight upward at 166 m / s. How fast is it moving at the instant it reaches the top of its trajectory? Correct answer: 0 m / s. Explanation: At the top of the trajectory the vertical component of the speed of the projectile is zero, so the speed is simply the horizontal component of the initial velocity. v = v x = 0 m / s 002 (part 2 of 2) 10.0 points How fast is it moving at the instant it reaches the top of its trajectory if the projectile is fired upward at 23 from the horizontal? Correct answer: 152 . 804 m / s. Explanation: v = v x = v cos = (166 m / s) cos23 = 152 . 804 m / s . 003 (part 1 of 3) 10.0 points A boy throws a ball upward. Compare the magnitudes of the gravitational accelerations at three points along the path of the ball. Point A is before the ball reaches the top. a) Point A on the way up. b) Point B is at the top. c) Point C is after it has passed the top and on the way down. B A C The magnitudes of the acceleration are re- lated as 1. a A < a B . 2. a A = g . correct Explanation: The gravitational acceleration near the sur- face of the earth is a constant, so the correct choice is a A = g . 004 (part 2 of 3) 10.0 points The magnitudes of the acceleration are re- lated as 1. a B > a C . 2. a B = a A . correct 3. a B = 0 . Explanation: The gravitational acceleration near the sur- face of the earth is a constant, so the correct choice is a B = a A . 005 (part 3 of 3) 10.0 points The magnitudes of the acceleration are re- lated as 1. a C = a B = a A . correct 2. a C < a B and a A < a B . Explanation: The gravitational acceleration near the sur- face of the earth is a constant, so the correct choice is a C = a B = a A . 006 (part 1 of 2) 10.0 points A particle has a constant acceleration vectora = schroeder (cs39963) Quiz 4: Two Dimensional Motion - Projectile and Circular Moton balasubraman (4 m / s 2 ) . At t = 2 sec, it has velocity vectorv = ( + ) (2 m / s). What is its velocity at t = 0? 1. (4 m / s) + (4 m / s) 2. vector 3. (2 m / s) + (6 m / s) 4. (2 m / s) (6 m / s) correct 5. (4 m / s) (4 m / s) Explanation: vectorv ( t ) = vectorv (0) + vectorat , so vectorv (0) = vectorv ( t ) vectorat = ( + ) (2 m / s) (4 m / s 2 )(2 s) = (2 m / s) + (2 m / s 8 m / s) = (2 m / s) (6 m / s) . 007 (part 2 of 2) 10.0 points After 2 sec, its position is found to be vectorr = ( ) (4 m)....
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Quiz 4 Solutions - schroeder (cs39963) Quiz 4: Two...

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