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Resource Quiz 1 - schroeder(cs39963 Resource I Units...

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schroeder (cs39963) – Resource I: Units, Dimensions, Conversions – Balasubramanya – (1401310) 1 This print-out should have 27 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The Resource Modules provide you a collec- tion of solved examples for your review before attempting questions. They are not for sub- mission for credit. 001 10.0 points What would equal 5 meters? 1. 50 cm 2. 50 dam 3. 0.5 km 4. 50 dm correct 5. 0.5 hm 6. 50 mm Explanation: (50 dm) · 1 m 10 dm = 5 m 002 10.0 points A school bus would have what relationship to a meter? 1. the same as 2. shorter than 3. longer than correct Explanation: “Waist high” on an average person is a fairly reasonable approximation for a meter. 003 (part 1 of 2) 10.0 points How many atoms are in a water molecule? 1. 1 2. 3 correct 3. 2 4. 4 5. 5 Explanation: H 2 O (water) has two hydrogen atoms and one oxygen atom for a total of 3 atoms. 004 (part 2 of 2) 10.0 points How many elements are in a water molecule? 1. 3 2. 5 3. 2 correct 4. 1 5. 4 Explanation: A water molecule is composed of hydrogen and oxygen. 005 (part 1 of 2) 10.0 points A perfectly spherical piece of metal is found at the bottom of a wishing well. The mass of the object is 1 . 15 kg and the radius is 0 . 19 m. What is its density? Correct answer: 40 . 0266 kg / m 3 . Explanation: Let : m = 1 . 15 kg and R = 0 . 19 m . The volume is V = 4 3 π R 3 = 4 3 π (0 . 19 m) 3 = 0 . 0287309 m 3 , so the density is ρ = m V = 1 . 15 kg 0 . 0287309 m 3 = 40 . 0266 kg / m 3 .
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schroeder (cs39963) – Resource I: Units, Dimensions, Conversions – Balasubramanya – (1401310) 2 006 (part 2 of 2) 10.0 points What would be its weight if it had the same volume and were made of pure gold? The density of pure gold is 19300 kg / m 3 . Correct answer: 5434 . 16 N. Explanation: W = m g = ( ρ V ) g = (19300 kg / m 3 ) (0 . 0287309 m 3 ) × (9 . 8 m / s 2 ) = 5434 . 16 N . 007 10.0 points One cubic meter (1.0 m 3 ) of aluminum has a mass of 2700 kg, and a cubic meter of iron has a mass of 7860 kg. Find the radius of a solid aluminum sphere that has the same mass as a solid iron sphere of radius 4 . 44 cm. Correct answer: 6 . 33971 cm. Explanation: Let : m Al = 2700 kg , m Fe = 7860 kg , and r Fe = 4 . 44 cm . Density is ρ = m V . Since the masses are the same, ρ Al V Al = ρ Fe V Fe ρ Al parenleftbigg 4 3 π r 3 Al parenrightbigg = ρ Fe parenleftbigg 4 3 π r 3 Fe parenrightbigg parenleftbigg r Al r Fe parenrightbigg 3 = ρ Fe ρ Al r Al = r Fe 3 radicalbigg ρ Fe ρ Al = (4 . 44 cm) 3 radicalBigg 7860 kg 2700 kg = 6 . 33971 cm . 008 10.0 points In 1990 there were approximately 7 × 10 6 people living in New York City. New York City has an area of approximately 8 . 31 × 10 2 square kilometers. What was the population density of New York City in 1990? Correct answer: 8423 . 59 people / km 2 . Explanation: Let : N = 7 × 10 6 people and A = 8 . 31 × 10 2 .
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