This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: schroeder (cs39963) Resource I: Units, Dimensions, Conversions Balasubramanya (1401310) 1 This printout should have 27 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The Resource Modules provide you a collec tion of solved examples for your review before attempting questions. They are not for sub mission for credit. 001 10.0 points What would equal 5 meters? 1. 50 cm 2. 50 dam 3. 0.5 km 4. 50 dm correct 5. 0.5 hm 6. 50 mm Explanation: (50 dm) 1 m 10 dm = 5 m 002 10.0 points A school bus would have what relationship to a meter? 1. the same as 2. shorter than 3. longer than correct Explanation: Waist high on an average person is a fairly reasonable approximation for a meter. 003 (part 1 of 2) 10.0 points How many atoms are in a water molecule? 1. 1 2. 3 correct 3. 2 4. 4 5. 5 Explanation: H 2 O (water) has two hydrogen atoms and one oxygen atom for a total of 3 atoms. 004 (part 2 of 2) 10.0 points How many elements are in a water molecule? 1. 3 2. 5 3. 2 correct 4. 1 5. 4 Explanation: A water molecule is composed of hydrogen and oxygen. 005 (part 1 of 2) 10.0 points A perfectly spherical piece of metal is found at the bottom of a wishing well. The mass of the object is 1 . 15 kg and the radius is 0 . 19 m. What is its density? Correct answer: 40 . 0266 kg / m 3 . Explanation: Let : m = 1 . 15 kg and R = 0 . 19 m . The volume is V = 4 3 R 3 = 4 3 (0 . 19 m) 3 = 0 . 0287309 m 3 , so the density is = m V = 1 . 15 kg . 0287309 m 3 = 40 . 0266 kg / m 3 . schroeder (cs39963) Resource I: Units, Dimensions, Conversions Balasubramanya (1401310) 2 006 (part 2 of 2) 10.0 points What would be its weight if it had the same volume and were made of pure gold? The density of pure gold is 19300 kg / m 3 . Correct answer: 5434 . 16 N. Explanation: W = mg = ( V ) g = (19300 kg / m 3 ) (0 . 0287309 m 3 ) (9 . 8 m / s 2 ) = 5434 . 16 N . 007 10.0 points One cubic meter (1.0 m 3 ) of aluminum has a mass of 2700 kg, and a cubic meter of iron has a mass of 7860 kg. Find the radius of a solid aluminum sphere that has the same mass as a solid iron sphere of radius 4 . 44 cm. Correct answer: 6 . 33971 cm. Explanation: Let : m Al = 2700 kg , m Fe = 7860 kg , and r Fe = 4 . 44 cm . Density is = m V . Since the masses are the same, Al V Al = Fe V Fe Al parenleftbigg 4 3 r 3 Al parenrightbigg = Fe parenleftbigg 4 3 r 3 Fe parenrightbigg parenleftbigg r Al r Fe parenrightbigg 3 = Fe Al r Al = r Fe 3 radicalbigg Fe Al = (4 . 44 cm) 3 radicalBigg 7860 kg 2700 kg = 6 . 33971 cm . 008 10.0 points In 1990 there were approximately 7 10 6 people living in New York City. New York City has an area of approximately 8 . 31 10 2 square kilometers....
View
Full
Document
 Fall '08
 STAFF
 Physics

Click to edit the document details