PHYS
Resource Quiz 6

Resource Quiz 6 - schroeder(cs39963 Resource 6 Circular...

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schroeder (cs39963) – Resource 6: Circular Motion and Gravitation – balasubramanya – (1401310) 2 3. v = radicalbig g R 4. v = μ radicalbig 2 π g R 5. v = radicalBigg g R μ correct 6. v = 2 radicalbig g R 7. v = 2 μ radicalbig g R 8. v = μ radicalbig 2 g R 9. v = radicalbig 2 μ g R 10. v = 1 2 radicalbig g R Explanation: Basic Concepts: Centripetal force: F = m v 2 r Frictional force: f s μ N = f max s Solution: The maximum frictional force due to friction is f max = μ N , where N is the inward directed normal force of the wall of the cylinder on the person. To support the person vertically, this maximal friction force f max s must be larger than the force of gravity m g so that the actual force, which is less than μ N , can take on the value m g in the positive vertical direction. Now, the normal force supplies the centripetal acceleration v 2 R on the person, so from Newton’s second law, N = m v 2 R .
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