Assignment #2 - Stephanie Campbell due at 11:55pm EDT...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Stephanie Campbell Assignment 2 MATH263, Fall 2010 due 09/18/2010 at 11:55pm EDT. You may attempt any problem an unlimited number of times. 1. (1 pt) Suppose that the initial value problem y = 9 x 2 + 5 y 2 - 7 , y ( 0 ) = 2 has a solution in an interval about x = 0. Find y ( 0 ) = . Find y ( 0 ) = . Find y ( 0 ) = . Note that for y ( 0 ) and y ( 0 ) you will have to differentiate the equation twice (remembering that y is a function of x ) and back substitute the values given or already calculated. The Taylor polynomial of degree 3 of the solution about x = 0 is ( T 3 y )( x ) = . 2. (1 pt) Find the function y = y ( x ) (for x > 0 ) which satis- fies the differential equation x dy dx - 7 y = x 9 , ( x > 0 ) with the initial condition: y ( 1 ) = 10 y = 3. (1 pt) Solve the initial value problem dy dx - 10tan ( 5 x ) y + 3sin ( 2 x ) = 0 , y ( 0 ) = - 4 . The solution is y ( x ) = 4. (1 pt) Find u from the differential equation and initial condition. du dt = e - 3 t - u , u ( 0 ) = 6 . u = 5. (1 pt) Find the function y = y ( x ) (for x > 0 ) which satis- fies the differential equation dy dx = 9 + 16 x xy 2 , ( x > 0 ) with the initial condition: y ( 1 ) = 5 y = 6. (1 pt) Consider the differential equation y = 1 36 x ( 81 - y 2 ) This equation has the 2 constant solutions (in increasing or-
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern