Results and Analysis

Results and Analysis - Results: Section 1 The following...

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Results: Section 1 – The following circuit was constructed: The measured values for the given parameters are shown in the table below: V ab 0 V V bc 0 V V ce 3.506 V V de 0 V V ad 3.506 V I 0 A The measured voltage V ad and V ce should be equal, which should be equal to the voltage of the source. V ad = V ce = 3.506 V ≈ 3.508 V (0.057% error) Section 2 – The following circuit was constructed:
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The measured values for the given parameters are shown in the table below: V ab 0 V V bc 3.505 V V cd 0 V V de 0 V V ad 3.506 V I 1 0.358 mA I 2 0 A The leftmost loop is a closed circuit, and thus there is current flow and a voltage drop across resistor R 1 . Using Ohm’s Law for this loop to match the IR value to the source V : V = IR ; V = (0.358 mA)(10 kΩ) = 3.58 V. This voltage drop ( V ad ) should be exact to the value of the voltage source due to Kirchhoff’s Voltage Law (KVL). Although they are relatively approximate to each other (3.58 V vs 3.508 V), the error is calculated as about 2.05%, which is still rather minimal. Section 3 – The following circuit was constructed: The measured values for the given parameters are shown in the table below: V ab 3.487 V V af 3.503 V V ai 0 V V id 3.50 V
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V ic 3.487 V V cd 16.33 mV I 1 0 A I 2 1.077 mA I 3 0.356 mA
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This note was uploaded on 12/02/2010 for the course EEL 3111L taught by Professor Zhongshang during the Fall '10 term at FIU.

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Results and Analysis - Results: Section 1 The following...

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