Homework 6-solutions - ahmed (ba6756) Homework 6...

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ahmed (ba6756) – Homework 6 – fakhreddine – (51010) 1 This print-out should have 33 questions. Multiple-choice questions may continue on the next column or page – Fnd all choices before answering. 001 1.0 points Consider the following reaction. 2 S + 3 O 2 2 SO 3 How much SO 3 can be produced from 96.0 g of O 2 and excess sulfur if the yield is 84.5%? 1. 1.69 g 2. 2.00 g 3. 304 g 4. 270 g 5. 135 g correct 6. Not enough information is given. 7. 189 g 8. 160 g Explanation: m O 2 = 96 . 0 g % yield = 84.5% ? g SO 3 = 96 . 0 g O 2 × 1 mol O 2 32 g O 2 × 2 mol SO 3 3 mol O 2 × 80 g SO 3 1 mol SO 3 × 84 . 5 100 = 135 g SO 3 002 1.0 points Which one of the following statements is ±ALSE? 1. Molecular orbitals are generally described as being more delocalized than hybridized atomic orbitals. 2. When one considers the molecular or- bitals resulting from the overlap of any two speciFc atomic orbitals, the bonding orbitals are always lower in energy than the antibond- ing orbitals. 3. Valence bond theory and molecular or- bital theory can be described as two di²erent views of the same thing. 4. One of the shortcomings of valence bond theory is its inability to account for the para- magnetism of O 2 . 5. One of the shortcomings of molecular or- bital theory is its inability to account for a triple bond in the N 2 molecule. correct Explanation: The molecular orbital theory predicts a bonding order of 3 for N 2 , which is equiva- lent to a triple bond. 003 1.0 points Which of the following is a true statement? 1. Bond strength, bond length and bond order are not related. 2. Stronger bonds have shorter bond lengths and larger bond orders. correct 3. Stronger bonds have larger bond lengths and larger bond orders. 4. Stronger bonds have larger bond lengths and smaller bond orders. 5. Stronger bonds have shorter bond lengths and smaller bond orders. Explanation: Bond order is an indication of bond strength. The bond order equals the num- ber of bonds. Triple bonds are shorter and stronger than double bonds which are shorter and stronger than single bonds. 004 1.0 points C 2 is calculated to have a bond order of two according to MO theory. Pick the true state- ment.
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ahmed (ba6756) – Homework 6 – fakhreddine – (51010) 2 1. The molecule has exactly two pairs of bonding electrons and no more. 2. The molecule is held together by two pi bonds. correct 3. The molecule contains one sigma and one pi bond. 4. The molecule is held together by two sigma bonds. 5. The molecule is paramagnetic. Explanation: The MO energy diagram will Fll with 8 total electrons (4 from each C). 4 electrons Fll the σ 2 s and σ 2 s MO’s. The order of the MO’s made with the overlapping 2p’s of the two C’s is π 2 p , π 2 p < σ 2 p < π 2 p , π 2 p < σ 2 p So the 2 π 2 p ’s Fll Frst meaning C 2 is held together with 2 π bonds and no σ ’s.
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Homework 6-solutions - ahmed (ba6756) Homework 6...

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