Keq 10 57 a 4 b 40 5 c 400 d 0 e 8 f 80 c h cl energy

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: H−Cl C H Cl C H−Cl C H Cl ∆ ∆H* = ? Keq = 10 ?/5.7 A ~4 B ~ 40 ≈5 C ~400 D ~0 E ~-8 F ~-80 C H Cl energy energy Keq = C H Cl C H−Cl 10?/5.7 C H Cl C H−Cl Δ Δ H° = 21 kJ/mol Keq = 104/5.7 ≈ 5 Δ Δ H° = 21 kJ/mol 3 reaction reaction Why is bromination more selective? Is the first step of bromination exothermic? CH3 H3C C CH3 CH3 H3C C H2C H+ H H+ 400 kJ/mol Cl H3C CH3 C CH3 432 kJ/mol Cl CH3 C CH3 CH3 C H2C H+ H H+ 400 kJ/mol Br H3C CH3 C CH3 366 kJ/mol +H Br +H H3C 421 kJ/mol Cl H3C CH3 432 kJ/mol C H2C H +H Cl H3C 421 kJ/mol Br H3C CH3 C H2C 366 kJ/mol H +H Br reactivity CH3 H3C C CH3 H + Cl2 initiator CH3 H3C C CH3 Cl + H3C CH3 C H2C H Cl + H Cl 3° 1° ≈5 C H C H Cl Cl C H−Cl 3° 1° ≈ 5 1 C H Br C H−Br C H Br 1600 3° ≈ 1 1° 37% 63% ΔH° = +55 kJ/mol energy energy C C H Br H−Br C H Cl C H−Cl CH3 H3C C CH3 H + Br2 initiator CH3 H3C C CH3 Br + H3C CH3 C H2C...
View Full Document

This note was uploaded on 12/05/2010 for the course CHE 321 taught by Professor Fowler/sampson during the Fall '08 term at SUNY Stony Brook.

Ask a homework question - tutors are online