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Unformatted text preview: Bio 201 My office hours Monday (12:50 to ~1:20; in Union cafeteria) Wednesday 1:302:30 (office number 616; 6th floor, Life Sciences) My lectures Will be posted on Blackboard within 24 hours after I give them I recommend reading the relevant chapter before class I recommend taking notes in class (notetaking is an important skill that you should try to develop!) Outline Evolutionary Processes Last Wednesday Why study evolution? Brief history of evolutionary biology Population geneticspart I Today Population geneticspart II Population Genetics Calculating Allele Frequencies Let p = frequency of A Let q = frequency of a p = 2N AA + N Aa 2N Why 2N? What will the formula be for q? Each individual has two alleles q = N aa + N Aa 2N Population Genetics Calculating Allele Frequencies If N AA = 150 and N Aa = 50, and N = 250, then what is p? What is q? p = 2N AA + N Aa 2N q = 2N aa + N Aa 2N Population Genetics Calculating Allele Frequencies If N AA = 150 and N Aa = 50, and N = 250, then what is p? What is q? p = 2N AA + N Aa 2N q = 2N aa + N Aa 2N p = 300 + 50 250*2 p = 350 500 q = ? p = 0.70 Population Genetics HardyWeinberg Equation In 1908, two scientists (Godfrey Hardy and Wilhelm Weinberg) independently came up with a fundamental idea in population genetics HardyWeinberg equation gives the expected frequencies of different alleles and genotypes (combinations of alleles) under simplified conditions How many AA individuals? How many Aa? How many aa? p 2 + 2pq + q 2 = 1.0 Population Genetics HardyWeinberg Equation Given random mating of individuals within the population (and many other assumptions) AA = p 2 (frequency of A * frequency of A) Aa = 2pq (2 * frequency of A * frequency of a) aa = what? Population Genetics HardyWeinberg Equation Given random mating of individuals within the population (and many other assumptions) AA = p 2 (frequency of A * frequency of A) Aa = 2pq (2 * frequency of A * frequency of a) aa = q 2 (frequency of a * frequency of a) Population Genetics HardyWeinberg Equation AA = p 2 (frequency of A * frequency of A) Aa = 2pq (2 * frequency of A * frequency of a) aa = q 2 (frequency of a * frequency of a) If p = 0.4, and N is 100, how many individuals have: AA? Aa? aa? Population Genetics HardyWeinberg Equation AA = p 2 (frequency of A * frequency of A) Aa = 2pq (2 * frequency of A * frequency of a) aa = q 2 (frequency of a * frequency of a) If p = 0.4, and N is 100, how many individuals have: AA = 16 individuals (p 2 = 0.4 * 0.4; p 2 = 0.16; N AA = 0.16 * 100) Aa?...
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This note was uploaded on 12/05/2010 for the course BIO 201 taught by Professor True during the Spring '08 term at SUNY Stony Brook.
 Spring '08
 TRUE

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