Wiens-lecture2-22March - Bio 201 My office hours...

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Bio 201 My office hours Monday (12:50 to ~1:20; in Union cafeteria) Wednesday 1:30--2:30 (office number 616; 6th floor, Life Sciences) My lectures Will be posted on Blackboard within 24 hours after I give them I recommend reading the relevant chapter before class I recommend taking notes in class (note-taking is an important skill that you should try to develop!)
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Outline Evolutionary Processes Last Wednesday Why study evolution? Brief history of evolutionary biology Population genetics–part I Today Population genetics–part II
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Population Genetics Calculating Allele Frequencies Let p = frequency of A Let q = frequency of a p = 2 N AA + N Aa 2 N Why 2 N ? What will the formula be for q ? Each individual has two alleles q = N aa + N Aa 2 N
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Population Genetics Calculating Allele Frequencies If N AA = 150 and N Aa = 50, and N = 250, then what is p ? What is q ? p = 2 N AA + N Aa 2 N q = 2 N aa + N Aa 2 N
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Population Genetics Calculating Allele Frequencies If N AA = 150 and N Aa = 50, and N = 250, then what is p ? What is q ? p = 2 N AA + N Aa 2 N q = 2 N aa + N Aa 2 N p = 300 + 50 250*2 p = 350 500 q = ? p = 0.70
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Population Genetics Hardy-Weinberg Equation In 1908, two scientists (Godfrey Hardy and Wilhelm Weinberg) independently came up with a fundamental idea in population genetics Hardy-Weinberg equation gives the expected frequencies of different alleles and genotypes (combinations of alleles) under simplified conditions How many AA individuals? How many Aa ? How many aa ? p 2 + 2 pq + q 2 = 1.0
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Population Genetics Hardy-Weinberg Equation Given random mating of individuals within the population (and many other assumptions) AA = p 2 (frequency of A * frequency of A ) Aa = 2 pq (2 * frequency of A * frequency of a ) aa = what?
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Population Genetics Hardy-Weinberg Equation Given random mating of individuals within the population (and many other assumptions) AA = p 2 (frequency of A * frequency of A ) Aa = 2 pq (2 * frequency of A * frequency of a ) aa = q 2 (frequency of a * frequency of a )
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Population Genetics Hardy-Weinberg Equation AA = p 2 (frequency of A * frequency of A ) Aa = 2 pq (2 * frequency of A * frequency of a ) aa = q 2 (frequency of a * frequency of a ) If p = 0.4, and N is 100, how many individuals have: AA ? Aa ? aa ?
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Population Genetics Hardy-Weinberg Equation AA = p 2 (frequency of A * frequency of A ) Aa = 2 pq (2 * frequency of A * frequency of a ) aa = q 2 (frequency of a * frequency of a ) If p = 0.4, and N is 100, how many individuals have: AA = 16 individuals ( p 2 = 0.4 * 0.4; p 2 = 0.16; N AA = 0.16 * 100) Aa ?
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