Unformatted text preview: f (2) x2 = lim x → 2f ( x )f (2) x2 ⇒ m = 4 . Therefore, b =4. 3. Diﬀerentiate y = csc θ ( θ + cot θ ). Solution. Use the product rule, y =csc θ cot θ ( θ + cot θ ) + csc θ (1csc θ cot θ ) =θ csc θ cot θcsc θ cot 2 θ + csc θcsc 2 θ cot θ 1...
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 Fall '06
 McAdam
 Calculus, Derivative, Cot, 2m, Guoliang Wu

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