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Unformatted text preview: t minutes as V = 5000 1t 40 2 , t 40 (1) Find the rate at which water is draining from the tank after 10 minutes. (2) At what time is the water owing out the fastest? The slowest? 1 Solution. (1) The rate at which water is draining from the tank after t minutes is V = 10000 1t 40 (1 / 40) = 25 4 ( t40) . (2) Since V is linear, at t = 0 the water is owing out the fastest, and at t = 40 the slowest. 2...
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This note was uploaded on 12/03/2010 for the course M 408c taught by Professor Mcadam during the Fall '06 term at University of Texas at Austin.
 Fall '06
 McAdam
 Calculus, Chain Rule, Derivative

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