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**Unformatted text preview: **t minutes as V = 5000 ³ 1-t 40 ´ 2 , ≤ t ≤ 40 (1) Find the rate at which water is draining from the tank after 10 minutes. (2) At what time is the water ﬂowing out the fastest? The slowest? 1 Solution. (1) The rate at which water is draining from the tank after t minutes is V = 10000 ± 1-t 40 ² (-1 / 40) = 25 4 ( t-40) . (2) Since V is linear, at t = 0 the water is ﬂowing out the fastest, and at t = 40 the slowest. 2...

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- Fall '06
- McAdam
- Calculus, Chain Rule, Derivative, 40 minutes, 10 minutes, Guoliang Wu, x2 + b2