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Unformatted text preview: x = 4 3 4 . 1 If x < 4 3 4, f ( x ) < 0, and if x > 4 3 4, f ( x ) > 0. Thus, f ( x ) has an absolute minimum at x = 4 3 4. In this case the length of the ladder is f ( x ) = (4 3 4 + 4) 2 + 64(4 3 4)2 (4 3 4 + 4) 2 14 . 5ft 2. Find f ( ) that satises f 00 ( ) = sin + cos , f (0) = 3 , f (0) = 4 . Solution: f ( ) =cos + sin + C 1 f ( ) =sin cos + C 1 + C 2 Since f (0) =1 + C 2 = 3, C 2 = 4. And f (0) =1 + C 1 = 4, C 1 = 5. Therefore, f ( ) =sin cos + 3 + 4 . 2...
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This note was uploaded on 12/03/2010 for the course M 408c taught by Professor Mcadam during the Fall '06 term at University of Texas at Austin.
 Fall '06
 McAdam
 Calculus

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