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Unformatted text preview: ME 16 Spring 2009 Midterm 2 Instructions: 1. Do not open this booklet until instructed to do so . 2. Write your name on this answer booklet. 3. Read each question carefully. 4. If you find that you are spending too much time on a problem, move on to the next and come back to it later. 5. Please, please, please write legibly. 6. To receive full credit you must show your work and explain clearly what you are doing. NAME: Solutions (revised) Problem 1 20% In the diagram below, a mass is initially suspended at rest in the position shown. L is the unstretched length of the springs, and both have equal spring constant k . When the mass is allowed to drop, it is observed that at the lowest point in its trajectory, each spring has length 2 L . Compute the spring constant k in terms of L and g (and m ). L 2L h 2L L Solution: Use h to denote the height drop, then h satisfies h 2 + L 2 = (2 L ) 2 , and thus h = √ L 2- 4 L 2 = √ 3 L. At the lowest point in the trajectory, velocity is zero and therefore kinetic energy is zero....
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This note was uploaded on 12/04/2010 for the course ECE 134 taught by Professor York during the Fall '08 term at UCSB.
- Fall '08