PS2 - 05 September 2010 Michael F Brown CHEMISTRY...

Info icon This preview shows pages 1–11. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
Image of page 7

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 8
Image of page 9

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 10
Image of page 11
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 05 September, 2010 Michael F. Brown CHEMISTRY 480A (Physical Chemistry) Problem Set 02 ____—__———_—————— To be turned in by: Monday, 13 September Worked examples for this course are dealt with primarily in the Discussion Section; whereas new concepts are introduced in the Lectures. You can get help with the homework problems in the Discussion Sections (14:00—14:50 Tuesday, Chemistry 209; and 15:30—16:20 Tuesday, Chemistry 134). The problem sets will be graded P+, P, or F and will be used to increase or decrease borderline grades. On all computational problems be sure to use SI units, and indicate your answer to the proper number of significant figures. For maximum credit show clearly how you obtained your answer, i.e. what numbers were combined to yield the final result. Background reading: Atkins & de Paula, Sections 1.1, 1.2 Back of Chapter Exercises related to the homework (optional): 1.2(a), 1.3(a), 1.4(a), 1.6(a), 1.7(a), 1.9(a), 1.10(a), 1.12(a) Back of Chapter Problems related to the homework (optional): 1.1, 1.3, 1.5, 1.25, 1.27, 1.31 Problem 1. Your research advisor has just purchased a very good laboratory vacuum pump that can generate a vacuum of about 1 nTorr. The temperature is 25 °C and assume that air consists of N2 molecules with a molecular collision diameter of d = 395 pm. a) Calculate the mean speed of the molecules. b) Calculate the mean free path of the gaseous molecules. 0) Finally, calculate the collision frequency of the molecules in the gas. Problem 2. A deep sea diving company has been called upon to attempt to plug an oil spill in the Gulf of Mexico. The diving bell has an air space of 3.0 m3 when at the surface. Assume the mean density of sea water is 1.025 g cm"3 and that the temperature is the same as on the surface. What is the volume of the air space when the diving bell has been lowered to a depth of 50 m? Problem 3. You are an atmospheric chemist and are investigating some technicalities of launching a meteorological balloon using the perfect gas law. Assume that the balloon has a radius of 3.0 m and that it is spherical. -1- a) What'amount of H2 gas (in moles) is needed to inflate the balloon to a pressure of 1.0 atm at an ambient temperature of 25 °C at sea level? b) What is the mass that the balloon can lift at sea level, where the density of air is 1.22 kg m‘3? c) What would be the mass the balloon can lift (the payload) if He gas were used instead of H2 gas? Problem 4. You are an organic chemist and wish to measure the molar mass of a newly synthesized (unknown) fluorocarbon using a gas microbalance. The device comprises a glass bulb forming one end of a beam, and the entire apparatus is contained within a closed chamber. The beam is pivoted, and the balance point is attained by raising the pressure of gas in the closed chamber, thereby increasing the buoyancy of the enclosed bulb. First, it is necessary to use a reference gas to calibrate the apparatus. The balance point is reached when CHF3 (M = 70.014 9 mole”) is introduced at 423.22 Torr. Next you can investigate the unknown sample. For the same setting of the pivot, the balance point is reached when the unknown fluorocarbon pressure was 327.10 Torr. Finally you repeat the experiment with a different setting of the pivot, which requires a pressure of 427.22 Torr of the CHF3 reference and 293.22 Torr for the unknown fluorocarbon. What is the molar mass of the fluorocarbon? Suggest a molecular formula. Problem 5. You are a chemical engineer helping out in an underdeveloped country. You are attempting to improve the Haber process as a means of producing better fertilizers for crop production. A reaction vessel of volume 22.4 L contains 2.0 mole of H2 gas and 1.0 mole of N2 gas at an initial temperature of 273.15 K. All the H2 reacts with sufficient N2 to form the NH3 product gas (ammonia). Calculate the partial pressures of the individual gases and the total pressure of the final mixture. Problem 6. An ideal gas is contained in a cylinder with a sliding piston and undergoes an isothermal expansion at T = 25 °C. The diameter of the cylinder is d = 10 cm. initially the mass on the piston is M = 10.0 kg and the initial volume is V1 = 6.00 L. Mass is removed from the piston and the gas expands to a final volume of V2 = 25.0 L. a) What is the final mass on the piston? b) What is the final pressure? 09-05-10 chem480A\10\prob\002\mw.doc mar fiffia ”Id/écw/es In a yd; x3 WQ/k/en 5%; $14:___-_213M mm __ , _, a ‘ '_ a?" v _A 7. 7 . 5‘9. 267/4 x3 g, van 4“ 3‘ 3:: if ““55: 97/” «jag/“SW A ’1] 2.1734? -_,C7/:/:.§:e02gc_ K_éd//_/S/6”P 6/255: sea/2m :033/3 0-73 ")(25+ 223 /5; ______________ 327(3)? 45V Mfg/n) (/X/o 77:9; )(4 023125” mfg/7’; A 776 u Tm!” =7 4 45§2x @7357 “WV ,. .3 .. _ _ _ 47—9/7‘e/uflerw’ufa : 4.246}? may _ fl / (>4 53x /0 357;:::: 4 455-31 4/047._m (.12 1551/1316. [7.6/(4/ (745 --_--WW WK}; - A» 1/, -. - v, = 3»? m3 - - WV: —- nflr‘ 236442426: r) W WW. -- - 564/ .5} ”337: 3‘ ’3: if; _ (E I: llpfi/ 03:1" $44.29 Cm 3/231 _Q It; 9 é); fwd. frat/Q-- (- A ::-.5:Q_la)__-W We (”‘23 gjké’c/ :74: ;c§/u'€ 29; m: 7/l'w‘fl VQ/ume ‘ n, _W-. . 13:3.) :02 V Z: Wei (Unify/”32:91:65 54:2 INN/“é? - _ _______ a--- ' V. - - _ -- - ”Ti“: _, W744; /_ 27/24/2097 (6...;er 13 -. . _ -_ - _ _ _ _- W _ - 10- f /- 4-- -M‘ng: . (Swfiml - ._ .. :_ _ _ - _ _ -. -. __ ‘ 65M ft ”‘22 42/2/47deij Wiggly <2me 0935/7615“ fifmfifim fl 1745;? a/f’pfé af A5“ 39144 ,_ inf/500W 2;, 7%6 -__. Janey-f, / 2-2. V65 W _- ___ -- - - 74’“ - : _W: _W W--:WW W _ : W. __ - :Q -- - _ W. -- 435:”ij +4? 7P: : 24/); > F @y/lfu/XMOW (fa/(e — V k :. i ( W _. WW .,...--WJ.___ WWW. H w _ fn/au‘m 3*— "Aféf';z_}<77>‘§[email protected]%uwu W - _ fl , ”Y V V m 4.7: 32+ 77/7791") (27: VA/>V:Vz:2—V%:)_VVVCVV A/m — ~— — :Wfidggéaa/r/{xs fé’xéafdg/ 79 flgwdé ,r‘fié” 79¢?” Mr‘réé’ “:‘fify‘tw 7m) {WU ((WiL (if: LQLZM7 I gag (2:737? fl;.fl_ N50911: 6%?” WWII/9w“ 5/; 2/“wa'wa/G/6M V _ “a a—ngefroVaVaZLVV—Cfiz/Q} Q- -VW 12. ”CW—F41” . ”é/(CO/gém ”$270-$777” fig} w (’Lwé jxr ;' . V: V/VV_ 3W /. C? a,» /_ W3 xvi)? K W' ”Ma/4r: MM _ A) Far 7‘7426 Q03: 4% i7?- Z/UM \ #172,227: fizVV-V'ZyfiQ-Véfiri AVIVV flmf/U‘Vn (damuu MW ; V ’ = 01 £4 ECQ 2.7 W 775 mm W 77,6 41mm 7/7344 45%}? g " f' ” ” ”(ff-’7. pr/Jg/Pa‘”. 3: 3 ‘ // W V C?— a/éLryCM-Qé’ :) Q 73:: 1.9%) ( V7417 / L10 is; ____:.:_____V. !/./ :7/ K/Mfi ii). _: / a 77.--: [d j V: __V V_:V_:.___ __ Ql/er‘ A- ._ ._ A, .4245-.. .. asWW-W Mao—W #54:.» 2222 W22 .224392; Z .-.-.WWEQW42M-WWW-WW- mg. 224 yam-21-42244 W W Wfl4zfléw 25W rag/422L- - 222-2222222222 292222222222 .) .2455.- (3.476 /c/€2(€ gay: __......,-‘_' ...; 222/: — 22 2%2: W W:-ffi: .1575: ' W: m".::..::: - WW6. -.--(fifram 3-24: #60 v4;- W fl/U2M ”t? 42-42 2422/22/25; _ .... ---W - . <7 ) M 7435152222222 222224222222 if» fio/Vzv 762: f4: {pr-cssace‘ .g/ V35: W WW - .-- W W 5(7 /) .M 6:, 2120226942 mm 43. 2%?- 292-522-2322 0223724 we 2.222. 2 22/22/22 2222. 5222:; 22E w .V (Mia/é. ..S.M<£5%¢.fié.€-s..2. 4—.er W WW».—W.-C.(-i?- 14.460923” f ¢2_Qn.c9-.g2vz/eah 44d @ E 62974:: - 7.464 «VJ-61 5,2241. .er/eW 4 Ka’ah (V é, WW. WWW WWW—W- . ...‘./,:. . :./>;2K _ 22-22._.222.é._ _ . W M g f; /472.. fog-(- .....-.- .- WW .WWWWW WWW- : . WWW- WWW 2227'— -. SJ/V/NQ {or "J4? rye/d2: lbw/'55 of‘fi/ie “yak/paw»; («452:2wrw 6:0: 24:63:; 77765;; <Mé>§74/ /Wf4//\14~ 34"?6 f7ddfl¢€ffiflfl (’44 4/3? 4‘1""? 2,326 3‘4""? W W-W WWWWWW 2 {'4 J -/ 7' . 2.»~122‘/.:2“ 2443;, - 3;: 71:22: ‘3 (77¢. 0/46/2422 ) W-- WWW _ ..W...-_ 4 38-773:- ((9.; 2 "Vb-2: Iii/W - _ . .-, .. 2. 70 555;; 2222.6 ‘4 . .. -WWWWWW :> M = 742952;; 2222/7 - W W WWWW I 7%6 . sécoznd _ gfifl/PJM/wC/‘J7L 2. -W W _W W :WW 22/:— (422222221 7‘ <22. 422% 2222/ (J _-_.W-._ W ,_ __ 243 2276rr , 2“: “MM . ..3. .402. Q// M-d/g-W _ - - _ W - - , 32/12: 20 2 0/ :27 222214 _::__W::__,:_ 7/7” VULMZ cf 174‘? ”40/4" I343 LU34 M) [S //¢I;;7»€2r M27 74/46 secoMC/«fli: .-.-W.- Rey-£22532» f-KW2M4W7424F25/W74 W. W42» 1’ _ 4"; c 795 71- a v W- -. 7711:: ,jém if Q 9‘7 (A46 91/? gig: (14443577 j/e'4/g ab éeéag/fdgj I 1,. w . ._‘ ,u_‘_r._ "“ “W W 7% “7/ 1 N — ef‘flér’ mflkf} 2‘. .4 ji/é‘é/ 14“”! £125 éwkdféf’p 1x41 féflggwh 7:4,; ._._ .. , _, / S /€E5 ”waim _ / biwggf {egg/{34 6/1/72: /Lh_ £4435 6 {34/3/92}; MJLH 9 5:? . m‘t’é‘é’ygé’m flf(@<h.._ié "3f? } “ix/l A“ .-_,-_“~-___..____ ___A/,-V_:if_:; <5 sf A€szzfiififwr€c>aW.» 1351,36"? .. in,“ . fi,,#,yg.._.-__.w-_..._.,_. 1., ,, k, ,. 7,» § _ a .10.: ' .- 5> 7772: Ol/er‘d// ngqq’wn 730/: “67423 292233» is 217%3323 @fdmwcan/a:_§s; - M 91-75,-” 31?" . .,’—_‘>+3/K’5/3-_ -_-,. 227-2229. ,:-:.<_>_.___,_ M. -n..(,2222).,.:-(3 N23 . 29.27.22 22;. .,..:.,=, -2333 2% (2/23) 2 333 0 4320 2;} WM’ 223.2373 _.--._,_,.-2- . J2 :2- 2— 2:) 2.22.2222, 2 ‘ 753, 71021231 frrcgng /J 7947 52.pr Q7? W flan/74! 023335122“; .3 7 - , 5-;12222 7+ 2 222;) +_ . 2 (22/23) “22:12::3: -,,,__w2.:.:33 + o. , .33 22M - --- ___._.~ ,..;.//’ 6 19F at/Qam’éd" 3473 WQ H36. 7446', aqMV-fm ofgmffll/ :nfii7i IN WM‘fifl‘fi Wfléndvd‘" 6% fit bib/2.2. We. v10 Jfav/Vy an 64% JEJQfiL WW? M6443, M fag/(lea is; N<w7£ong éecOmcl L33.) F:mg?) Whara— 6’) "9» 65"? jrdV/F/LM'WM acceépafiofi ' 6C) App/6’3»)? b4? @Mfagf @013 L4 (A) wévb avert/“4471‘” : fi/U/ lib/27'" =~ Pgl/Q“ S/Noz. e9: PJrCa/Aréic‘k 3-4 ”3/19“ M/ V/ “‘ ”hwy?‘ :> Mad: (vi/m) M, : (:Zii (mm/g) I 29 4'0 #6?“ A) 7/66. [)‘fl‘aé prfsgtw 5:; m..:/ti fhé flfczdf arm/It? 4071;ka m/Qm “fag, MCI/)4...— M; éy/ca/W abéJGU-E. : P%: ””93 : ”42>; /4f 7 F?‘ ézx/ Fax/(fa; 07C" yam/m :mo//OQ\ :: _ -Q« ., m (294Loéf)(7r<80?x45) :aflqu/o’g/gMSQ/V/Q‘ m m2 x (aw) 9* w A/ : 3000 Pat; p?) m P69 fir“ F2» I I : grwgwagloéfla f/(fi/M onzx @574 ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern