HW1-Ch23 - kim(hk7467 Homework 1(Chapter 23 kang(GEDB023-41...

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kim (hk7467) – Homework 1 (Chapter 23) – kang – (GEDB023-41) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points A uniformly charged ring of radius 4 . 5 cm has a total charge of 49 μ C. The value of the Coulomb constant is 8 . 98755 × 10 9 N · m 2 / C 2 . Find the magnitude of the electric field on the axis of the ring at 1 . 2 cm from the center of the ring. Correct answer: 5 . 23154 × 10 7 N / C. Explanation: Let : a = 4 . 5 cm = 0 . 045 m , Q = 49 μ C = 4 . 9 × 10 - 5 C , k e = 8 . 98755 × 10 9 N · m 2 / C 2 , and x = 1 . 2 cm = 0 . 012 m . The electric field is E = k e x Q ( x 2 + a 2 ) 3 / 2 = (8 . 98755 × 10 9 N · m 2 / C 2 ) (0 . 012 m) (0 . 012 m 2 + 0 . 045 m 2 ) 3 / 2 × (4 . 9 × 10 - 5 C) = 5 . 23154 × 10 7 N / C . 002 (part 2 of 4) 10.0 points Find the magnitude of the electric field on the axis of the ring at 4 . 72 cm from the center of the ring. Correct answer: 7 . 49481 × 10 7 N / C. Explanation: Let : x = 4 . 72 cm = 0 . 0472 m . E = (8 . 98755 × 10 9 N · m 2 / C 2 ) (0 . 0472 m) (0 . 0472 m 2 + 0 . 045 m 2 ) 3 / 2 × (4 . 9 × 10 - 5 C) = 7 . 49481 × 10 7 N / C . 003 (part 3 of 4) 10.0 points Find the magnitude of the electric field on the axis of the ring at 44 cm from the center of the ring. Correct answer: 2 . 23951 × 10 6 N / C. Explanation: Given : x = 44 cm = 0 . 44 m . E = (8 . 98755 × 10 9 N · m 2 / C 2 ) (0 . 44 m) (0 . 44 m 2 + 0 . 045 m 2 ) 3 / 2 × (4 . 9 × 10 - 5 C) = 2 . 23951 × 10 6 N / C . 004 (part 4 of 4) 10.0 points Find the magnitude of the electric field on the axis of the ring at 112 . 392 cm from the center of the ring. Correct answer: 3 . 47795 × 10 5 N / C. Explanation: Let : x = 112 . 392 cm .
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