# finalprep - CHEM 251 Phys Chem for Engineers December 2009...

This preview shows pages 1–3. Sign up to view the full content.

CHEM 251 Phys. Chem. for Engineers December 2009 Final Exam Prep: Voluntary Quiz As well as all material constants and coefficients that you will need in the required units, the following formulae will be given to you: p + a n V 2 ( V - bn ) = nRT (0.1) p = nRT V - bn - a n V 2 (0.2) d E cv d t = d Q d t + d W S d t + ˙ m h H spec 1 - H spec 2 + g ( h 1 - h 2 ) + 1 2 ( v 2 1 - v 2 2 ) (0.3) 1 v 0 ([ S ] 0 ) = [ S ] 0 + K M v max [ S ] 0 (0.4) = 1 v max + K M v max 1 [ S ] 0 . (0.5) 0–1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
1. The Coulomb potential between two particles i and j in one dimension is defined as: V ( x i , x j ; e , q i , q j ) = q i q j e ( x i - x j ) - 1 , (0.6) where q i and q j are the particle point charges and e is the dielectric constant. Calculate the forces f i and f j exerted on the particles due to this potential energy function. 2. For the following rate expressions, state the order of the reaction with respect to each species, the total rate order of the reaction and the units of the rate constant, k : (a) Rate = k [ ClO ][ BrO ] (b) Rate = k [ NO ] 2 [ O 2 ] (c) Rate = k [ HI ] 2 [ O 2 ] [ H + ] 1 2 3. Calculate the ratio of rate constants for two thermal reactions
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern