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Unformatted text preview: MA 160 Section 3.3 Worksheet Name 6:. G as; t'am
A   iications: Uninhibited and Limited Growth Models. E ntial Gr wth.
“any ,m y=Ce'“ W kt ° . .
dr P(t) = P0 e where k is the exponential growth rate. In 1 and 2, ﬁnd the eneral form of the ﬁmction that satisﬁes the iven diﬁ'erential  uation: ﬂ
d1 3. Approximately 10,000 bacteria are placed in a culture. Let P(t) be the number of bacteria present
in the culture after t hours, and suppose that P(t) satisﬁes the differential equation P’U) = 0. 55P(t) . :1. Find the formula for P(t). b. What is P(0)?
F1473: {game e asst .5519) P(0): io’me — t
d. What is the exponential growth rate ?
K zeta“; c. How many bacteria are there after 5 hours? 49(5) : to we 6";56).
’  fféj‘faé, f. What is the size of the bacteria culture when it is
growing at the rate of 34,000 bacteria per hour? P’Cf): 052; Purl
34am : ~56" PC?)
34,6199
.5; e. Use the differential equation to determine how
fast the bacteria culture is growing when it
reaches 100,000. P‘Zé) :3 a $500,009) 3" 555342 We.
Pelt/«gm 4. Suppose a population is growing with exponential growth rate 0.04. In how many years will the current
population triple? Peg1 :, Pa 6 If t’ t E 3 3P0 : Paeoa‘tt
3 to‘tt
1" "a C «911.3: wattt': M3
'0‘} ; é 5. How much money must you invest now at 6% interest compounded continuously in order to have $5000 at the
end of 3 cars?  , K e
Y P (:t ) a Pa (2 n
n. .09 ; .0G(3\
5000:: Poe 30.;
5m ‘ Fa
«06(3)
500a $5
“W:Pa 0L Po 2 ‘H’ve.35‘ e
gaawm £4€I7éo3§Wa~¥vmdéc )ﬁ'gjzaae 3500:: l
W3gwwa «fWaeh CW6 W 3 a 3
6. The population of the United States in the year 1776 was about 2.5 million. In its bicentennial year, 1976, the
population was 216 million. Assume that at any time, the population grows at a rate that is proportional to the
I o ulation at that time. a. Find the exponential growth rate and round your b. Assuming 1? 76 corresponds to t = 0, what is the
answer to 4 decimal places. t = 0 M i"! 7 a, function that models this situation? c. What is the estimated U.S. population for 2010?
t ... .2010 r77@ :2 23‘! P523“: n.5'e‘09‘303“ d. Using the differential equation corresponding 6 In what War Will this 1901911151’6101‘:l “33011 350 million?
to this problem, what is the growth rate in 2010? 3‘50 5‘ at 5 e ' 0 lag t P’Hzlzeogast Pa) 350 gonna
,s east 7. $5000 is deposited into a savings account at 3% compounded continuously. a. Wl/i‘at is the formula for A(t), the balance after t years? b. What differential equations is satisﬁed by A(t) ?
(f):500@ 8803f: A’Cf):o03A(éJ c. How much will be in the account alter 4 years? d. When will the balance reach $8,000? A(q) : Socoe.03(‘ll: gas)?! (1,? :_Hb;i:3i.03f
5000 east
g: = 8 ﬁ=i5',(o’7
e. flowfastis the balance growing when it reaches $8,000? Jone?) =lm~3+ game.
A (8:..03‘Eidél]: .03(§coa):$¢)qﬂ.m Mtg!)
W4.— ’ 9 g :s f 8. An amount of money is deposited in a savings account with interest compounded continuously. Let A(t) be the
balance in the accOunt after t years. Match each of the following questions with its corresponding solution. Solution
A. A(t) = Pe ’ ‘ B. A(0) C. Find MS) D. Find A'(5) E. Solve A(t) = 5 for t .
F. Solve A'(i)=5 fort. D a. How faml the balance be growing in 5 years?
A b. Give the general form of the function A(t)
H o. How long will it take the initial deposit to grow to ﬁve
times the initial deposit?
C (I. Find the balance after 5 years. The. a?» 9 C 53
E e. When will the balance be $5?
F_ f. When will the balance be growing at the rate of $5 per year?
5 g. What was the principal amount? L" W '—' 5 Q h. Give a differential equation satisﬁed by A(t) G. y' = ry or A’(i) = rAU)
H. Solve A(t) = 5*A(0) fort . ...
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This note was uploaded on 12/05/2010 for the course MATH MA160 taught by Professor Guyton during the Spring '10 term at Montgomery CC.
 Spring '10
 Guyton

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