Chem Lab 1 - density of an unknown sample I also learned...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Determination of Density Thursday, April 15, 2010 Chem 1031-015 Procedure: Pick one larger and one smaller sample from the same unknown sample bin. Remember the
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
number of the bin and write it down on the data sheet. Weigh a clean 50-mL beaker on the analytical balance and record it. Then weigh each sample, one at a time, while inside the beaker. Record the values on the data sheet. Then obtain the volume of each same by putting one into an already water- filled graduated cylinder and record the mL, and then put the other sample in and record the mL. Do the same previous procedures for two new different samples, again getting on large and one small each time. The last two times you generate the mass of each sample, you use a semi-analytical balance and a triple beam balance. Conclusions and Reflections: During the Determination of Density Lab, I learned how to calculate the mass, volume, and
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: density of an unknown sample. I also learned how to use those numbers to find the average density, percent error, and molar volume of the sample. The only problem that I encountered was the lack of triple-beam balances. I liked how the lab taught me to be precise while taking measurements and to double check my answers. Questions: 5) I believe that my unknown sample was Aluminum (Al). I think this because my average density of 2.79 g/mL was closest to Aluminum's average density of 2.70 g/cm^3. 8) Density of solid carbon dioxide = 1.560 g/mL-D = m/v-V = m/d-V = 6.9 g/ 1.560 g/mL-V = 4.4 mL-mass = 6.9 g-volume = ?-6.9 grams of dry ice would occupy a volume of 4.4 mL. 9) Specific gravity of mercury = 13.60-volume = 4.55 mL-mass = ?-D = m/v-M = dv-M = 13.60(4.55 mL)-M = 61.88 g-When a sample of mercury occupies a volume of 4.55 mL, the mass is 61.88 g....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern