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Unformatted text preview: density of an unknown sample. I also learned how to use those numbers to find the average density, percent error, and molar volume of the sample. The only problem that I encountered was the lack of triple-beam balances. I liked how the lab taught me to be precise while taking measurements and to double check my answers. Questions: 5) I believe that my unknown sample was Aluminum (Al). I think this because my average density of 2.79 g/mL was closest to Aluminum's average density of 2.70 g/cm^3. 8) Density of solid carbon dioxide = 1.560 g/mL-D = m/v-V = m/d-V = 6.9 g/ 1.560 g/mL-V = 4.4 mL-mass = 6.9 g-volume = ?-6.9 grams of dry ice would occupy a volume of 4.4 mL. 9) Specific gravity of mercury = 13.60-volume = 4.55 mL-mass = ?-D = m/v-M = dv-M = 13.60(4.55 mL)-M = 61.88 g-When a sample of mercury occupies a volume of 4.55 mL, the mass is 61.88 g....
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- Fall '08
- Chemistry, Kilogram, unknown sample, average density