lect27cor - AS = S     1 2 n ...

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MATH1111/08Fall/Lecture 27 - Correction 1 MATH1111 - Correction In the proof for ” A has n linearly independent eigenvectors A is diagonalizable”, there is a mistake: I wrote AS = λ 1 λ 2 . . . λ n S. This is wrong , the correction is AS
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Unformatted text preview: AS = S      λ 1 λ 2 . . . λ n      . [Recall S denotes S = ( x 1 x 2 ··· x n ) where x 1 , ··· ,x n are the n linearly independent eigenvectors and n is the order of A .]...
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