- Math 1110 Practice Prelim 3 Solutions 1 Evaluate the following limits if they exist If a limit does not exist explain why(a lim θ →(1 θ csc

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Unformatted text preview: Math 1110 Practice Prelim 3 Solutions 1. Evaluate the following limits if they exist. If a limit does not exist, explain why. (a) lim θ → (1 + θ ) csc( θ ) (b) lim x → 1 x 3 (c) lim x →- 3 x 2- x- 12 x +3 Solution: (a) Writing L = lim θ → (1 + θ ) csc( θ ) , we have ln( L ) = lim θ → ln((1 + θ ) csc( θ ) ) = lim θ → ln(1 + θ ) sin( θ ) . This is a 0 / 0 indeterminate form, so l’Hˆ opital’s Rule applies. Therefore ln( L ) = lim θ → 1 1+ θ cos( θ ) = 1 . So lim θ → (1 + θ ) csc( θ ) = L = e 1 = e . (b) As x approaches 0, the denominator approaches 0, while the numerator stays constant at 1. So the limit does not exist. (c) Using l’Hˆ opital’s Rule, we see that the answer is- 7. 2. Evaluate the following expressions. (a) R π cos( x ) dx (b) R 2 x x 1- t 2 dt (c) d dx R x 2 a sin( t ) dt (d) R (sin(2 θ )) e sin 2 θ dθ Solution: (a) 0 (b) x- 7 x 3 3 (c) 2 x sin( x 2 ) (d) Let u = sin 2 θ so that du = 2sin θ cos θ = sin(2 θ ). Then R (sin(2...
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This note was uploaded on 12/06/2010 for the course MATH 1110 taught by Professor Martin,c. during the Fall '06 term at Cornell University (Engineering School).

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- Math 1110 Practice Prelim 3 Solutions 1 Evaluate the following limits if they exist If a limit does not exist explain why(a lim θ →(1 θ csc

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