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Unformatted text preview: 12/7/10 Chemistry basics Physical properties Force energy 12/7/10 Physical properties Chemistry the study of matter and the changes it undergoes Matter anything that has mass and occupies space States of matter solid, liquid and gas 12/7/10 Physical properties cont. Physical properties A characteristic that can be observed without changing the identity of the substance. Chemical property the ability of a substance to change into another substance 12/7/10 Physical properties cont. Base Units Unit Symbol measurement meter m length Kilogram Kg mass second s time 12/7/10 Physical properties cont. SI prefixes Prefix Symbol factor pico p 1/1012 nano n 1/109 micro 1 1/106 milli m 1/1000 centi c 1/100 kilo k 1000 12/7/10 Physical properties cont. Unit conversions converting between units Conversion factor = given units required units 12/7/10 Physical properties cont. Dimensional analysis Example how many microseconds are in one year sec 10 15 . 3 sec 1 sec 10 min 1 sec 60 1 min 60 1 24 1 365 1 13 6 x hr d hr yr d yr = 12/7/10 Physical properties cont. Practice example Calculate the volume in cm3 for a box having the dimensions 1.0 ft x 2.0 ft x 3.0 ft 12/7/10 Physical properties cont. Volume of the box is 6.0 ft3 ( 29 ( 29 ( 29 ( 29 3 3 3 3 3 3 901 , 169 . 1 54 . 2 . 1 . 12 . 6 cm in cm ft in ft = 12/7/10 Force and energy Force = mass x acceleration (F=ma) Units: F = kg x m/s2 = N 12/7/10 Force and energy cont. Energy capacity to do work Work motion against an opposing force Joule (J) unit of energy 12/7/10 Force and energy cont. Calorie is the unit of energy required to raise one gram of water by 1.0 degrees Celsius from 14.5 oC to 15.5 oC. 1 Cal = 4.184 J 12/7/10 Force and energy cont. Kinetic energy energy in motion units = kg x m2/s2 = N x m 2 2 1 mv E k = 12/7/10 Force and energy cont. Potential energy energy based on current position or state. m = mass , g = gravity , h = height units again = kg x m/s2 x m = N x m mgh E p = 12/7/10 Force and energy cont. Coulomb potential energy attraction or repulsion due to electric charges. q1 and q2 = charge of particle in coulombs r q q E p = 12/7/10 Coulomb potential energy Calculate the Coulomb potential energy found (in eV) in a hydrogen atom where the proton and electron are separated by 53 pm? given 1 eV = 1.602e19 J 12/7/10 Force and energy cont. Therefore and k = 4 1 : let r q kq E p 2 1 = 10 99 . 8 2 9 C m J x k = 12/7/10 Total energy 2 2 1 mv E k = 2 2 1 Force of Law s Coloumb' r q kq f = = r mv ma f 2 also = = 12/7/10 Total energy cont....
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 Spring '10
 Freeman
 Chemistry, pH, States Of Matter

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