chapter22-part2 - Electric field of a point charge E = EA =...

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1 Electric field of a point charge 2 0 0 2 4 1 ) 4 ( r q E q r E EA E ± = ± = = = Φ πε ε π Applying Gauss’s Law • Select the Gaussian surface, such that the point of interest lies on the surface • This surface must me some imaginary geometric surface, not a real surface. It may be in empty space, embedded in a solid body, or both. • We evaluate Gauss’s law on the surface. We pick it such that a geometric symmetry of the charge distribution helps us to simplify the calculation (sphere, cylinder)
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Electric field in a conductor Under electrostatic conditions, charges do not move. This means that E inside the conductor is zero, or otherwise charges would move. Calculate the flux through an arbitrary Gaussian surface inside the conductor. Since E =0 , the flux will be zero, meaning, there is no charge enclosed by the surface. Since this can be done for an arbitrary surface, we conclude that the charge resides at the surface !!! Field of a charged
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This note was uploaded on 12/08/2010 for the course PHYSC 1220 taught by Professor Feiguin during the Fall '10 term at Univeristy of Wyoming- Laramie.

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chapter22-part2 - Electric field of a point charge E = EA =...

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