Final+Exam+Sample+Problems+-+solved

Final+Exam+Sample+Problems+-+solved - R163. A skis: starts...

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Unformatted text preview: R163. A skis: starts from rest at, A (30 ft, 0) and dascent’xs the: smoath 510;»: which may be appmximatad by a parabai‘a. :fshe has a weight {£120 :memrminmhe manna} force: shy: ekefis on the ground at the instant she arrivas at paint 8. ‘ mnwmmmwmmgfiu W‘Nmmw «WWMNMMWWMNWWWMW VCQVMSEVWRNMWQM mi? Eklézgfflflj 3:: Ya? «a a) g - “"‘“""““""’“"“'""“‘“ W” WW” %+*\l“ :Tfifiv 9;” v4 \méw‘E "*’ Vb “I? 9-9:; f N kg 1:: 5\.O‘% W5 NOKi/Eméxn Acaerucrfififflg’w 2 F“ 1; Mg“ \r2 m (35‘ of?) g :2: .52 Z om : /€ w a was” 353%; NMW 3:” m Ck“ e. w QMij wag W N3 (we a» no 30 mm m 17~97. The spool has 'of 100 kg ahd a radius of gyration kg =. 0.3 r'mLIVf (H3 'ctgbffiéients of static and kinetic; . friction at A are: pl, élQLZL‘éhd‘ p); 220.15, respe'ctivei , determine the ahgular accéler'aiion of the spéol if P = 600 N. figLW gx Q‘» '3'" , Qtfi‘zfii/fiw 411% '3 if? m E M ' 5% 6:7) M CM 4:: CK 5&{33 gm wwcw Fm 2 mm!) mg N > MW in {EEK u 122-18.- The dljum of mass 'm, radius 1', and ragiius of gyratiah k0 rolls along an inclined plants for which the , coefficient of static‘friction is ,u. If the drum is reléased from rest, determine the maximum angle 8 for the incline so that it rolls without slipping. ' kcx 2: w. 35“ Maigng N m 6.005)); Ex} W m & Mtge“ (>4 ~» WW; (:3) SHE “33 émifi {i W‘fiémfi :. MrMKW€ZQ§ Q WWWMMM.WWM‘ W9.me W» “I; *RZ~24. The pendulum consists of a 30-113 Sphsre and a 10413 siender rod. Compute the reaction at the pin 0 just after the cord AB is cut. ' {:33 is» “F; 2:: m 61% m? 03% Mfg {3% €19 fl «3 i?» C2533} 4% Z a: Mada fimfiy Qt} 4” 4O 3 3m OW {fig} (4» ‘Zszejgmk W393"? 40(25) :2 CKVF?‘®K gm 2: Z . ‘35 d ALTGQ'MNVQ : $91.,»an W4“ w .m g“ m M: \OflD Mtg/$2, 1M0 ~ ZEN +7ma *2. ‘2» 0w; 21. W33 “fig/32’ 30%} % WU) "+ 13%?“ (X W 4» H 32. Z“ w "2 2'“ m M m 2.3 m ~» W CM (“My mm) gawk" (a W $5“ if: 2: Man 0., (mm: a”; Mo B is :14: rest and spool A is mtafing fit 6 rad/s ~ ' wfisn the slack in the: cogd cannecfing than: is {@3532 fig}; De£emine ‘che aggumgyggggity (:5 Each 39ml irrifimdiétely . after $316: mg jaggéaflfight‘ The; spomsll~ and B have: ’Waighfianq gymtion WA m 3015'? kg ,~"'"~ 9.8 ft and Wg‘m 1513f}? respeatively; r ‘ ' ‘3 {3, mum "5m «mavmx‘m 1%» {wwflfi‘b gag; (ma? Q; «W Wrwggggg B {3062 ifWacM, SWQL 15 fl Wax} ‘3” ZfMg) .5.» {m T(o,4¢)a :: (any)? Mfg P I K k N G; MAM 6,3 \Yz; 73 W13, 2.. @i%q ileum?” L w 1: '2 YES 9”“ M T “39% M W No W2; «,WWWWM mwwmmmwmwww W1-uwa‘nMmcwmzmwrmwrmrfllmmxwmwé mnwmvmpmmm - “WW, “MANN/M, MMWMMWW/M;mwwmmwmwmwmpwmmmmmmmwWWMWWWWampwaw The 10—kg rod A}? shown in Fig. 18~19a is confinfid so that its ends move in the harizontal and vertical 310m. syrimg has a sfiffnesg of k z 800 N/m and is unsftretched when 6* 2 00. Detemdne the anguiar velocity of AB when 8 2 0", if the rod is released from rest when 9 z 300. Negiect the mass of the, Sfififfi‘ biccks. ~ 'Efivmm WM K‘W * *xmxmf % (:0 h)%&{&, “44mg m3 0“? Q'Mévmféz‘ké Z (a . I C1 2 0. 25999 “:3 m “4" 0' “l The linkage ABD is formed by connecting two 4-kg b a collar of negligible mass. The motion of {ha linkage is controlled Force P applied to the collar. Knowing that at the instant shown the an velocity and angular acceleration of bar AB are zero and :10 rad/32 Clockwise, respectively, determine the force P. ’ 0.9 m I 3’? QB C053: ‘7 41 L“ ‘j OLD S§4(,gc):01dlb< RI) Q5) 9v Mafia: “1/32 O‘igw 11> QWQ/gz tiles: 1“: qweij 4, Fivfiil'éeeéfifi l? G 9 » "Tile? ‘” gin» M Q; l/alldclc’ am?” at 0’21"!» Ella RX?) EMA“: “1.76% 4.5 Bdofl) z: Vfififloflfilzflo} ““““ Vijf m 3: l2 . o N a EKR RD 5' 23M, a wwéw“)lmzzgfzxgvm‘; "W'sz’weéfi‘sfl =2: “aawfréxzé-W) m, (aflqym’m) m 4 { %.?~V“%»)5gf¢9,4§§{j& Mil M233 35‘ 2 N MAM”lWWW”M.,aWWWm.mmmmmmwwwwmmmmnwmwmmmm, r {(0 . (2, Co Aux—“gm Mngw gm. W1le '~ ‘1“ :6 @523 @4335? 73m fig 3' as J luau“? Mfaz‘ i u; M _ “3:. “ 5.21:: ‘” u a is? ' A ~ M fig“ 534:3 W” “55:? if»; “(0% $3“: ' ' ED ” 5 I 3% :7 RAV35 D ilk I OLD/s m dglbwwmw f. w Q 3 \o. a”; w}? z i 0 0M x: a , E ... WW1!) 3 55’ Km; 6:: Maw?” S»; E ; MEN/«t? ' 3" S»??? > M; _¢A«. ‘1': 1% i: 2%: % am “‘3” gas, Bra //5> (KG-333m} I (“5&7 gagg 3 “5WQ'31[0,¢5»§”§ 4 aim/$3- Ba» / a {1‘ "a m‘iw mi % 4 ! (mm32.$m_. é AW} % g {Maj} T gm. E3”: (mmkgl 3,, [22% ‘5 M ‘ m K , y“ W. jgfié‘ng, 8:2 , k: ‘N “M Q” 3 m W“ ‘ ‘37 M 4! W 63 A932 W M A“: $702 Eb p a) m 2: 3,; m1?» mm)» M msggm‘) Vfifljfiw 3” “NW N @ 2F] 2 B} -4¢[¢%fét) wPaCfiQ-gQB + N 5;“ {00 : “MQQEQ a: méfimfizfig’axfigfij +2 5 EN _ 1 ‘5:- 4(%%l)(0.<¥§’> a» “Pg/x (BQXOS‘Q «w Nggflg‘mwgqu) : TOME?) “fl/émixofijfi Gil?) W: AEg , A?) ...
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Final+Exam+Sample+Problems+-+solved - R163. A skis: starts...

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