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Unformatted text preview: Draw/Reduce Mesh until the desired fineness is achieved (256 elements is a good choice). Continued … PROBLEM 4.66 (Cont.) After hitting Run , C heck and then Calculate , use the View/Temperature Contours and select the 10-isopotential option to display the isotherms as shown in an annotated copy of the FEHT screen below. The isotherms are normal to the symmetrical lines as expected since those surfaces are adiabatic. The isotherms, especially near the center, have an elliptical shape. Along the x = 0 axis and the y = 10 mm axis, the temperature gradient is nearly linear. The hottest point is of course the center for which the temperature is T(0, 10 mm) = 401.3 K. < The temperature of this point can be read using the View/Temperatures or View|Tabular Output command . (b) To determine the required generation rate so that T(0, 10 mm) = 600 K, it is necessary to re-run the model with several guessed values of q . After a few trials, find ± 8 q 1.48 10 W / m = × ± 3 <...
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This note was uploaded on 12/07/2010 for the course MAE Heat Trans taught by Professor Lee,j.s. during the Spring '10 term at Seoul National.
- Spring '10
- Heat Transfer