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Operating parameters for a representative BWR design is given below.
For the BWR average channel compute and
plot the mixture and phase velocity distributions.
Determine the individual components of and the total pressure
drop.
Compare the results obtained using both equilibrium and non equilibrium models.
You may assume the
saturation properties are constant along the length of the channel and may be evaluated at the system pressure.
BOILING WATER REACTOR PARAMETERS
Core Averaged Heat Flux
144,032 Btu/hrft
2
Pressure
1000 psia
Coolant Mass Flux
1.42 x 10
6
lbm/hrft
2
Core Inlet Temperature
532 F
Rod Pitch
0.640 inches
Rod Diameter
0.493 inches
Fuel rods per bundle
64
Bundle Dimensions (canned)
5.278 x 5.278 inches
Upper and Lower Tie Plate Loss Coefficient
3.5
Number of grids
7
Grid Loss Coefficient
0.5
Fuel Height
146 inches
Axial Peak to Average Ratio
1.4
The axial heat flux may be taken to be
′′
+
⎛
⎝
⎜
⎞
⎠
⎟
+
⎛
⎝
⎜
⎞
⎠
⎟
qz
q
Hz
H
H
ee
()
=
(
)
)
0
πλπλ
sin
You may assume the twophase friction multiplier is given by the expression
75
.
1
2
2
)
1
(
1
20
1
x
o
−
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
+
+
=
χ
φ
A
where
is the turbulent Martinelli parameter and given by
μ
ρ
2
02
18
1
=
⎛
⎝
⎜
⎜
⎞
⎠
⎟
⎟
−
⎛
⎝
⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎜
⎞
⎠
⎟
⎟
f
g
g
f
x
x
.
.
and that the Homogeneous Multiplier derived in class is valid for the local losses.
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View Full DocumentSOLUTION
Heat Flux Profile
The heat flux profile is given as
′′
+
⎛
⎝
⎜
⎞
⎠
⎟
+
⎛
⎝
⎜
⎞
⎠
⎟
qz
q
Hz
H
H
ee
()
=
(
)
)
0
πλπλ
sin
The average channel is defined such that
∫
′
′
=
′
′
H
ave
dz
z
q
H
q
0
)
(
1
For the heat flux profile given here
⎪
⎭
⎪
⎬
⎫
⎪
⎩
⎪
⎨
⎧
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
+
+
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
−
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
+
+
−
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
′
′
=
′
′
e
e
e
e
e
e
ave
H
H
H
H
H
H
H
H
H
H
q
q
)
(
sin
sin
)
(
cos
)
(
cos
0
λ
π
πλ
which for
032
,
144
=
′
′
ave
q
may be solved directly for
0
q
′
′
giving
5
0
10
108
.
1
×
=
′
′
q
Btu/hrft
2
.
Enthalpy Distributions
The enthalpy distribution is given by the simple energy balance
hz
h
m
qz D
d
z
z
±
=+
′
′
∫
0
1
0
where the mass flow rate is given by
x
GA
m
=
±
and
4
/
2
2
D
S
A
x
−
=
.
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 Fall '08
 Doster

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